A 100kg person landing from a vertical jump has a vertical Momentum of -885kg-m/s upon impact with the ground. If it takes.6sec for him to come to a complete stop, what is the average Vertical Ground Reaction Force during the landing?
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Q: A teen of mass m = 64 kg travels at a velocity vi = 1.55 m/s before jumping on a skateboard. After…
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A: The objective of the question is to find the mass of the Tunguska meteor given its kinetic energy…
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- The Moon’s craters are remnants of meteorite collisions. Suppose a fairly large asteroid that has a mass of 4.95 × 1012 kg (such an asteroid is about a kilometer across) strikes the Moon at a speed of 14.5 km/s relative to the Moon. What is the change in kinetic energy, in joules, in the collision? Such an event may have been observed by medieval English monks who reported observing a red glow and subsequent haze about the Moon.The Tunguska meteor delivered 1.2E17 Joules of kinetic energy to the Earth’s atmosphere in an air-burst over Siberia in 1908. If its speed was 2.7E4 m/s, what would its mass have been?Can you help me with this physics problem? A 0.35 kg projectile is moving in the negative y direction at a speed of 55 m/s. It collides and embeds in a 7.2 kg mass moving in the positive x direction with a speed of 5.1 m/s. What is the final velocity of the two masses? What fraction of energy was lost in this collision using Kinetic energy with this formula (Ki-Kf)/Ki
- A baseball of mass m = 0.35 kg is dropped from a height h1 = 2.85 m. It bounces from the concrete below and returns to a final height of h2 = 1.39 m. Neglect air resistance.Randomized Variablesm = 0.35 kgh1 = 2.85 mh2 = 1.39 m a. What is this impulse, in kilogram meters per second? b. If the baseball was in contact with the concrete for t = 0.01 s, what average force Fave did the concrete exert on the baseball, in newtons?How do I solve this using either the momentum/velocity model?this is a multi step problem but I am just having trouble with this part of the problem. Here are the values that I correctly calculated: mass of particle 1=6 kg initial velocity for particle 1= 185i+138j final velocity for particle 1= -68.89i+-50.67j I am trying to find: What is the change in kinetic energy for particle 1? I understand I have to use KT= 1/2*m*(vf2-vi2) but I keep getting the wrong answer can you please help?
- A woman with a mass of 59 kg runs at a speed of 6 m/s and jumps onto a giant 30 kg skateboard initially at rest. What is the combined speed of the woman and the skateboard?A 6.2 g bullet is fired into a 179 g block that is initially at rest at the edge of a frictionless, 0.6 m high table. The bullet remains in the block, and after impact, the block lands 2.9 m from the edge of the table. What was the speed of the bullet before impact?We substitute the known values into the conservation of momentum equation MVi + mvi = MVf + mvf to obtain (66.0 kg)(0 m/s) + (1.35 kg)(2.25 m/s) = (66.0 kg)Vf + (1.35 kg)vf. Because vf = Vf, this further simplifies to (66.0 kg)(0 m/s) + (1.35 kg)(2.25 m/s) = (1.35 kg + 66.0 kg)Vf. What is the velocity of the astronaut after the collision?
- MO-6 The Meteor Crater in Arizona is about 1,200m wide and 200m deep. It is believed to have been formed 20,000 years ago when a meteor with a mass of 5.0x10"kg moving at 7.2km/s collided and merged with the earth. If the earth had been at rest prior to the collision, what would the speed of the earth have been after this collision? The mass of the earth is 5.98x10"kg. 24A 3.25 µg particle moves at 2.09 × 10° m/s. What is its momentum p? p = kg-m/sWhat is the numeric answer to problem #24 on page 293? This is a fairly challenging problem.Just remember that Momentum is conserved __________________