A = 1000 mm a = 40 mm² h, = 500mm h, = 300mm 1000x 20 500 log 10 300 K = 2.303- 40 x180 K = 1.42 cm/sec Hence hydraulic conductivity in cm/s is 1.42. Step3 c) Head difference at time t =100sec AL h K = 2.303- log 10 (i) at L = 200 mm = 20 cm t=100 sec A = 1000 mm² a = 40 mm h = 500mm h, = h =? K = 1.42 cm/s 1000 x 20 500 -log10 h 1.42 = 2.303 40 x 100 Calculate above equation with the help of scientific calculator 1.42 x 40x 100 500 log10 h 2.303x1000x 20 h =376.4 mm

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Show me the step by step procedure on how did you find the value of k because if you input it in calculator i get 10.66
A = 1000 mm²
a = 40 mm?
= 500mm
= 300mm
1000x 20
500
log 10
K = 2.303
40×180
300
K = 1.42 cm/sec
Hence hydraulic conductivity in cm/s is
1.42.
Step3
c)
Head difference at time t =100sec
AL
K = 2.303-
at
„(i)
h.
L = 200 mm = 20 cm
t =100 sec
A = 1000 mm²
a = 40 mm
h = 500mm
h, = h =?
K = 1.42 cm/s
1000x 20
500
-log10
40 x 100
1.42 = 2.303
h
Calculate above equation with the help of scientific calculator
1.42 x 40x 100
500
log10
%3D
2.303x1000x20
h = 376.4 mm
?
VX
Transcribed Image Text:A = 1000 mm² a = 40 mm? = 500mm = 300mm 1000x 20 500 log 10 K = 2.303 40×180 300 K = 1.42 cm/sec Hence hydraulic conductivity in cm/s is 1.42. Step3 c) Head difference at time t =100sec AL K = 2.303- at „(i) h. L = 200 mm = 20 cm t =100 sec A = 1000 mm² a = 40 mm h = 500mm h, = h =? K = 1.42 cm/s 1000x 20 500 -log10 40 x 100 1.42 = 2.303 h Calculate above equation with the help of scientific calculator 1.42 x 40x 100 500 log10 %3D 2.303x1000x20 h = 376.4 mm ? VX
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