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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.

A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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A 100-kg box is towed to move horizontally from rest by a constant force P=200 N. The kinetic friction is μk =0.1. The angle of the force P is θ=30° with respect to the horizontal direction.  The acceleration due to gravity is g=9.81 m/s2. 

 

(3) Select the expression of the friction force F. ___________




 
 

  A.

F=μN
  B.

F=μP
  C.

F=μmg
  D.

F=0
A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s² (3) Select the expression of the friction force F. O A F=UN O B. F=uP O C.F=umg O D.F=0 P
Transcribed Image Text:A 100-kg box is towed to move horizontally from rest by a constant force P-200 N. The kinetic friction is μ =0.1. The angle of the force P is 8-30° with respect to the horizontal direction. The acceleration due to gravity is g=9.81 m/s² (3) Select the expression of the friction force F. O A F=UN O B. F=uP O C.F=umg O D.F=0 P
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