A 100 ha watershed has the following characteristicsi. Maximum length of travel of water in the catchment = 3500 mii. Difference in elevation between the most remote point on the catchment and the outlet-65 miii) runoff coefficient = 0.331The maximum intensity - duration - frequency relationship for the watershed isgiven byi3.9770.165===(D+0.15) 0.733te = 0.01941077 -0.385where i = intensity in cm/h, T = Return period in years and)=duration of rainfallin hours (concentration time). Estimate the 25-year peak runoff from the watershed that can beexpected at the outlet of the watershed.

Step 1: Calculate the Concentration Time (tc)Given the formula for concentration time:…

Answered: A 100 ha watershed has the following…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A reservoir is to be constructed with the following characteristics: Mean Annual Runoff, MAR =50mm Catchment Area = 286km2 Coefficient of Variation CV= 110% Full Supply Capacity FSC = 8x 106m3 What is the probability that the reservoir will fill to full capacity from empty in one year assuming that the runoff data follows the Weibull distribution function? P(X-x) = 1-e^(aX/x)b
Develop the SCS triangular unit hydrograph for a 375-acre watershed that is an industrial district. The flow length is 1275 feet, the slope is 2.75 percent, and the soil is group C. Plot the resulting hydrograph. (similar to 8.8.1)
A catchment has four sub-areas. The annual precipitation and evaporation from each of the sub-areas are given below. Assume that there is no change in the groundwater storage on an annual basis. Compute the runoff coefficient for the Sub A. Show complete Solution
5. From the 1mm 6 hour unity hydrograph given below, derive the 2 hour unit hydrograph. Time 12 18 24 30 (hrs) UH 15 8 3.6 0.6 0.0 (cumecs) What would be the peak surface runoff resulting from 3mm of rainfall falling in the space of two hours?
Compute the 4-hr Snyder's synthetic unit hydrograph for a watershed with an area of 27.8 square miles and a main channel length of 16.3 miles. The main channel length from the outlet to the point opposite the centroid of the watershed is 5.4 miles. The regional parameters are C₁ = 1.7 and C₂ = 0.5. Plot the resulting hydrograph and label the lagged time to peak (tr), time to peak (TDR). peak discharge (Q₂R), and time base (T₁). (similar to 8.4.4)
6. Runoff from a 200 mile² catchment drains into a reservoir than has an average surface area of 4000 acres. The reservoir is to be used for municipal water supply. Annual rainfall over the watershed is 40 inches and the annual runoff is 2 inches. Evaporation from the reservoir averages 40 inches per year. If the surface area of the reservoir is roughly constant with depth, how much will the reservoir depth change in one year?
Solve the problem using the NRCS method for a watershed located right outside New York City, New York for a 50 year storm event. Assume the soil hydrologic group B (65%), C (25%) and D (10%). Given Am-1.29 sm. Impervious = 6.6 acres, Woods =819 acres. Overland flow: L=100 ft, s=4%, fair; Shallow Concentrated Flow: unpaved L= 2300 ft, s=2.7%, stream flow L=9000 ft, s= 3.4% The Time of Concentration is 20¹ 12¹ n = 0.035
The ordinates of a 6h-UH of a watershed having a drainage area of 393 km^2 are given below. For a storm over the watershed having excess rainfall of 5 cm for the first six hours and 15 cm for the second six hours, compute the direct runoff hydrograph ordinates and plot the hydrograph. Compute the depth of direct runoff in cm. Assuming constant baseflow of 100 m^3/s, compute the storm hydrograph ordinates and plot the hydrograph. (List all the DRH ordinates in order, separated by a single space.)
An 40-ha watershed was subjected to a 5- year rainfall with a depth of 122 mm with characteristics given below. Compute for the peak runoff of the watershed. Hydrologic Soil Group Land Use, Area Curve Treatment, and (ha) Number Condition Row crop, 24 82 contoured, good Woodland, good В 16 55
2 %V9 li. 3 (9 This question requires one response per row The base flow for this direct runoff hydrograph is: 0 4 8h o Index = 0.135 cm/h Rainfall excess = 5.52 cm 30 25 20 15 Direct runoff 5.52 cm 10 A Base flow -6 0 12 18 24 30 36 42 48 54 60 66 Time in hours -6 8 5.52 48 Discharge (m/s) 3.26 cm 2.26cm

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