A 10.00 ml. sample of Y(OH)2 was titrated to the stoichiometric point with 14.50 ml of 0.2345 M H2X. The total number of moles of Y(OH)2 is O a. 0.00469 O b. 0.0068 Oc. 0.00034 O d. 0.0034

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hi! Please answer B and C.

B
All of the following will likely result to a lower calculated molarity of NAOH titrant EXCEPT:
O a. There is an air space at the burette tip all throughout the titration process.
O b. The initial volume (Vo) of the burette was not recorded when the actual NaOH solution was % of its
volume capacity
o. The inner wall of the e-flask containing the KHP solution was not rinsed with distilled water even though
the NaOH titrant has dripped down the inner wall during the titration process.
o d. The purity of KHP standard was taken as 100% when in actual it was not.
A 10.00 mL sample of Y(OH)2 was titrated to the stoichiometric point with 14.50 mL of 0.2345 M H2X. The total
number of moles of Y(OH)2 is
O a. 0.00469
O b. 0.0068
Oc. 0.00034
O d. 0.0034
Transcribed Image Text:B All of the following will likely result to a lower calculated molarity of NAOH titrant EXCEPT: O a. There is an air space at the burette tip all throughout the titration process. O b. The initial volume (Vo) of the burette was not recorded when the actual NaOH solution was % of its volume capacity o. The inner wall of the e-flask containing the KHP solution was not rinsed with distilled water even though the NaOH titrant has dripped down the inner wall during the titration process. o d. The purity of KHP standard was taken as 100% when in actual it was not. A 10.00 mL sample of Y(OH)2 was titrated to the stoichiometric point with 14.50 mL of 0.2345 M H2X. The total number of moles of Y(OH)2 is O a. 0.00469 O b. 0.0068 Oc. 0.00034 O d. 0.0034
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