A (10 Kg mass) block is resting on a rough horizontal surface for which the coefficient of friction is (u=0.30). Determine the force P applied to the block. EFx=0 3Pcos30-F=0 2P F=3Pcos30 3 P EFy=0 N-98.1-3Psin30-2P=0 0-30 N=98.1+3Psin30+2P F=u N 3Pcos30=0.3*(98.1+3Psin30+2P) PD F= N=

A (10 Kg mass) block is resting on a rough horizontal surface for which the coefficient of friction is (u=0.30). Determine the force P applied to the block. EFx=0 3Pcos30-F=0 2P F=3Pcos30 3 P EFy=0 N-98.1-3Psin30-2P=0 0-30 N=98.1+3Psin30+2P F=u N 3Pcos30=0.3*(98.1+3Psin30+2P) PD F= N=

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: ) The uniform crate has a mass of 20 kg. If a force P = 80 N is applied on to the crate, determine…

A: Given:Mass of the crate, m=20 kgForce applied on the crate, P=80 N

Q: QI-The W=250o-N block shown in Fig. below is in contact with 30° incline. The coefficient of static…

A: Given W=2500 N μs=0.25 P=? θ=30o

Q: Q1-A 75-Kg man wants to pull a 145- Kg box and the coefficient of static friction between the box…

A: Given data Mass of man = 75kg Mass of box = 145 kg. Coefficient of static friction between box and…

Q: the photo, the man has a mass of 60 kg and the crate has a mass of 100 kg. The coefficient of static…

A: For the solution refer below images.

Q: The uniform crate has a mass of 35 kg. If a force P = 85 N is applied on to the crate, determine the…

Q: A 6.00 kg block is pressed against a vertical wall by a force. The coefficient of static friction…

A: Given: The mass of the block pressed against a vertical wall is mi=6.00 kg. The coefficient of…

Q: 2.1. Demonstrate all forces acting on a car. 2.2. Calculate the acceleration of the caravan if the…

A: Given Datam1=600kgm2=400kgF1=m1g=600×9.81=5886NF2=m2g=3924Nμs=0.25 Here the free body diagram…

Q: Determine the horizontal force that must be applied to the fifth block from the top of the stack, in…

A: Number of Block = 6Force acting on the block= 5NThe coefficient of static friction between the…

Q: Q1: - The block shown in figure below has a mass of 100 kg and is resting on 30° inclined surface.…

Q: A horizontal force of P = 100 N is just sufficient to hold the crate from sliding down the plane,…

Q: 3. Blocks A and B have a mass MA and MB, respectively. If the coefficient of static friction between…

Q: Select the correct statement to represent the above problem (Answers are more than one).

A: (J) Correct explanation- The us = 0.3 is the coefficient of static friction that can be…

Q: g mass) block is resting on a rough horizontal surface for which the nt of friction is (u=0.30).…

A: m=10 kgμ=.30

Q: A 0.8 lb roll of paper is suspended from a wire hanger so that it rests against the wall. The hanger…

Q: The end A of the beam needs to be raised slightly to make it level. If the coefficient of static…

Q: The coefficient of static friction for both wedge surfaces is 0.44 and that between the 31-kg…

A: This question is solved with the help of the equilibrium equation. Equilibrium conditions " States…

Q: A ladder is leaning against a vertical wall, and both ends of the ladder are at the point of…

A: Given:Coefficient of friction between surface and ladder, μA=0.245Coefficient of friction between…

Q: ient of static friction at the floor is μs = 0.4. a) Determine the maximum force ‘P’ that can be ap

Q: (a) A force F pushes on a 25kg box as shown in the figure. The coefficient of static friction…

Q: The crate has a weight of 490 lb and a center of gravity at G rests on the floor for which the…

A: Let m = Mass of crate =490lb = 221.97kg g= Acceleration due to gravity =10m/s2 W = Weight of crate…

Q: The crate has a weight of 490 lb and a center of gravity at G rests on the floor for which the…

A: Given data: - The weight of the crate is W = 490 lb. The coefficient of static friction is μ =…

Q: Activity 1. A 25-kg ladder, 4 m long, rests on a rough floor and against a vertical wall. The ladder…

Q: Q1 - A 75-Kg man wants to pull a 145- Kg box and the coefficient of static friction between the box…

A: 1) To Find : The tension force in the cable. Given : The mass of man is m=75 kg. The mass of box…

Q: PROBLEM 1: Two blocks A and B, each having a mass of 5 kg, are connected by the linkage shown in the…

A: Step 1:Step 2:Step 3:Step 4:

Q: kg block is placed on the uniform 10-kg beam, that is supported by the cable, which is attached to…

A: Given:Mass of the block, mb=40 kgMass of the cantilever beam, mc=10 kgCoefficient of static…

Q: نقطة واحدة A (10 Kg mass) block is resting on a rough horizontal surface for which the coefficient…

A: Any action that can change the state of motion is called force. Newton's second law states that the…

Q: contacting surfaces that are unequal; the segment aligning with the motion of the belt or band has a…

A: The mass of block A is ma=59 kg The static friction coefficient between the block and the surface is…

Q: A chain having a length L and weight W rests on a street for which the coefficient of static…

Q: 15 30

Q: A 40-kg block is placed on the uniform 10-kg beam, that is supported by the cable, which is attached…

A: Given:Mass of the block, mb=40 kgMass of the beam, mc=10 kgCoefficient of friction, μ=0.6

Q: 7. A box of unknown weight is being pulled on a 0 = 39 degree inclined surface by a frictionless…

Q: Calculate the horizontal force Pon the light 11° wedge necessary to initiate movement of the 36-kg…

Q: The coefficient of static friction for both wedge surfaces is 0.37 and that between the 27-kg…

Q: The 100 – Ib force acts as shown on a 300 – Ib block placed on an inclined plane. The coefficients…

A: weight of block=300lb force=100lb

Q: Object A exerts 18,000lb force on wedge E. Object A and wedges E & F are made of steel and have a…

Q: el ramp is used by a worker in a factory to move a cardboard box. The box weighs 40 lb with a center…

A: Given:W=mg= 40 lbμ=0.3NOTE: According to Bartleyby's policy we shall answer only three sub-parts so…

Q: A 150-lb block rests on a horizontal floor. The coefficient of friction between the block and the…

Q: Determine the magnitude of the friction force (assume down and to the right is positive). The mass…

A: To determine the magnitude of the friction force, we need to consider both the static and sliding…

Question

Hw.3
A (10 Kg mass) block is resting on a rough horizontal surface for which the
coefficient of friction is (u=0.30). Determine the force P applied to the block.
EFx=0
3Pcos30-F-D0
2P
F=3Pcos30
3 P
EFy=0
N-98.1-3Psin30-2P=0
0-30°
N=98.1+3Psin30+2P
F=u N
3Pcos30-0.3*(98.1+3Psin30+2P)
750
PD
F=
N=

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Hw.2 A (10 Kg mass) block is resting on a rough horizontal surface for which the coefficient of friction is (u-0.20). Determine the force Papplied to the block. EFx=0 5Pcos45-F=0 5P F=5Pcos45 45 EFy=0 N-5Psin45-98.1=D0 N=98.1+5Psin45 265 F=u N 5Pcos45=0.2*(98.1+5Psin45) P= F= N=
QUESTION 2 Determine the value of P just sufficient to start the 920 wedge under the W lb blue block. The angle of friction is p for all contact surfaces. Neglect the weight of the orange block. The surface numbers are in light green highlight F2 = F3 = P P = 01 02 W ❤ 45 15 300 18 Answer in three (3) decimal places including zeros F1 = lb lb lb 2 lb 3 deg deg lb deg 02 01
P (N) * 2. The force P is applied to the block m kg, which is stationary before the force is applied. Determine the magnitude and direction of the friction force f exerted by the horizontal surface on the block. m kg 30° H = 0.80 H = 0.60 %3D Figure 2. 25 kg m = .... ..... .... .. P = 245.25 newton ....... ..... .......
Six 5 N blocks are stacked vertically. The coefficient of static friction between the blocks is µs = 0.20. Determine the horizontal force that must be applied to the fifth block from the top of the stack, in order to slide it out without moving the other blocks.
Part B Determine the maximum force P that can be applied without causing movement of the 110-kg crate that has a center of gravity at G. The coefficient of static friction at the floor is Us = 0.38. Assume that tipping occurs. Figure 1 of 1 Express your answer to three significant figures and include the appropriate units. 0.5 m, 0.5 m µA ? P = 110 0.8 m Submit Previous Answers Request Answer 1.5 m 1.2 m X Incorrect; Try Again; 3 attempts remaining Provide Feedback Next >
40 kg object is being pushed downwards at an angle of 32° with the horizontal. If the coefficient of static friction is 0.4 and dynamic friction 0.35. Determine (a) what must be the applied force P to overcome static friction and (b) what will be the required force P if the box is already moving. P 32° 40kg
A mountain camper has problems with his off road vehicle. To hold it in place the camper wraps a rope abound a treen + turns. The coefficient of friction between the rope and the tree is u. = 0.23. The car pulls on its end of the rope with a force of 2250 N. The camper wants to pull on the rope with a force no greater than P = 54 N. P Determine the integer value of n. (Enter the minimum possible integer value of n.)
Q1- In the arrangement shown in Fig ,what is the minimum coefficient of friction to prevent the 8.0kg mass from sliding? 30° 8.0 kg 4.0 kg
(ii) The block on the left incline is 6kg. Find the mass of the block on the right incline so that the system is in equilibrium (no acceleration). All surfaces are frictionless. (ii) Determine the tension in the string if the coefficient of static friction is 0.4. 6 kg 0210 60° m = ? 25° boosts zi sqon A odTgd of 30 laups i onge
A system is in equilibrium with the 150 Ibs block having a coefficient of friction of 0.4. Determine the coefficient of friction of the 100 lbs block. Pulley 150 Ibs 100 Ibs 45° 30