format in solving:1. given2. diagram (simple labeled sketch)3. solution (use formula from formula sheet)4. therefore statement (full answer with correct sig figs) A 1.75 kg mass is released from restat a height 60.0 cm above a light verticalspring of force constant k. The ball strikesthe top of the spring and compresses it adistance 8.90 cm. neglecting any energylosses during the collision, find the forceconstant of the spring.ma FORMULA SHEETMotion Equations:Gravitational, Electric and Magnetic Fields:dVave =Vavg =dr = d, + d2 + d3 + ……ü = v, + ätGMmF =GMmE, =-d, = d, + dz + dz+.F, == kai =+ ü)td = ö,t +d = öt -ü2 = v,? + 2ädkogE =ΔΕAV =V = kqAE, =-AEv²a. =q = Ne= BIT sin 0F = Bqü sin 0HNIRelative Motion:B = ANIForces:Modern PhysicsEnet = må= mỹF, = µFNFnet = F, + F2 + F,+...AtoAt =L = L. 1m =Energy and Momentum:E = mc? – m.c?E =- moc²p = müAp = F At= mAip = p'Constants:т — т,g = 9.8 m/s² [Down]k = 9.0 × 10° N - m² /C?e =1.60 x 10-19CH. = 47x10"T - m/ Ac = 3.0 x 10* m / sv,'= v,|т, +т,= AmüElasticCollisionsG = 6.67 x 10-11 N-m²/kg²2m,v,'= v,m, + m,M, = 5.98×10ª kgEarthr = 6.37×10ʻmm, =1.67×10" kgm¸ = 9.11×10~" kg }Atomr, = 5.29×10"mE, -mE. = kx?W = F. Ad cos0AE¸ = mgAh

Name: format in solving:1. given2. diagram (simple labeled sketch)3. solutio
Uploaded: 2024-03-20T06:57:25.000Z
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Description: format in solving:1. given2. diagram (simple labeled sketch)3. solution (use formula from formula sheet)4. therefore statement (full answer with correct sig figs) A 1.75 kg mass is released from restat a height 60.0 cm above a light verticalspring of