* A 1.74 g/L solution of NaCl (Molecular weight = 58 g/mol) is put in a conductivity cell which gives a resistance of 300 ohm at 3O C. The same conductivity cell is put in a solution of CaCl2 (10000 mg in 0.5 L), the cell records 800 ohm. If the conductivity of NaCl solution is 0.002 ohm /cm. CaC12 Molecular weight = 111g/mol. Calculate the molar conductivity of the CaCl2.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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* A 1.74 g/L solution of NaCI
(Molecular weight = 58 g/mol) is put
in a conductivity cell which gives a
resistance of 300 ohm at 30 C. The
same conductivity cell is put in a
solution of CaCl2 (10000 mg in 0.5
L), the cell records 800 ohm. If the
conductivity of NaCl solution is 0.002
ohm /cm. CaCI2 Molecular weight =
111g/mol. Calculate the molar
conductivity of the CaCl2. *
Transcribed Image Text:* A 1.74 g/L solution of NaCI (Molecular weight = 58 g/mol) is put in a conductivity cell which gives a resistance of 300 ohm at 30 C. The same conductivity cell is put in a solution of CaCl2 (10000 mg in 0.5 L), the cell records 800 ohm. If the conductivity of NaCl solution is 0.002 ohm /cm. CaCI2 Molecular weight = 111g/mol. Calculate the molar conductivity of the CaCl2. *
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