A 1.51-kg steel sphere will not fit through a circular hole in a 0.753-kg aluminum plate, becuase the radius of the sphere is 0.10% larger than the radius of the hole. If both the sphere and the plate are kept at the same temperature, how much heat must be put into the two so that the ball just passes through the hole? Number i Units ✪

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**Problem Statement:**

A 1.51-kg steel sphere will not fit through a circular hole in a 0.753-kg aluminum plate, because the radius of the sphere is 0.10% larger than the radius of the hole. If both the sphere and the plate are kept at the same temperature, how much heat must be put into the two so that the ball just passes through the hole?

**Response:**

- Number: [Input field for numerical answer]
- Units: [Dropdown for selecting units]
Transcribed Image Text:**Problem Statement:** A 1.51-kg steel sphere will not fit through a circular hole in a 0.753-kg aluminum plate, because the radius of the sphere is 0.10% larger than the radius of the hole. If both the sphere and the plate are kept at the same temperature, how much heat must be put into the two so that the ball just passes through the hole? **Response:** - Number: [Input field for numerical answer] - Units: [Dropdown for selecting units]
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