Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected through a resistance R = 7.50 so the apparatus forms a complete electrical circuit. Ignore the resistance of the bar and the rails and all gravitational effects. [c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.

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Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a
uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected
through a resistance R = 7.5Q so the apparatus forms a complete electrical circuit. Ignore the
resistance of the bar and the rails and all gravitational effects.
[c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.
Transcribed Image Text:Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected through a resistance R = 7.5Q so the apparatus forms a complete electrical circuit. Ignore the resistance of the bar and the rails and all gravitational effects. [c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.
Expert Solution
Step 1

The emf induced due to the motion of the metal bar is 

ε=vBl

where ε is the emf, v is the velocity, B is the magnetic field and l is the length of the bar. 

The current is given as

i=εR

i=vBlR  .............................. (1) 

The power is equal to 

P=i2R

 

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