Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected through a resistance R = 7.50 so the apparatus forms a complete electrical circuit. Ignore the resistance of the bar and the rails and all gravitational effects. [c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.
Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected through a resistance R = 7.50 so the apparatus forms a complete electrical circuit. Ignore the resistance of the bar and the rails and all gravitational effects. [c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.
Related questions
Question
![Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a
uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected
through a resistance R = 7.5Q so the apparatus forms a complete electrical circuit. Ignore the
resistance of the bar and the rails and all gravitational effects.
[c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F474861d3-aaf1-4b4c-afe2-e250091335e4%2F548c338e-8b52-48a3-8237-052baf5ef7d4%2Fa0acjhs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Prob. 4 A 1.2m-long metal bar is pulled to the right at a steady rate of 2.5m/s perpendicular to a
uniform, 1.50T magnetic field. The bar rides on a pair of conducting, parallel rails connected
through a resistance R = 7.5Q so the apparatus forms a complete electrical circuit. Ignore the
resistance of the bar and the rails and all gravitational effects.
[c] How much energy (in units of J) is dissipated at R over a 3.0sec interval.
Expert Solution
Step 1
The emf induced due to the motion of the metal bar is
where is the emf, v is the velocity, B is the magnetic field and l is the length of the bar.
The current is given as
.............................. (1)
The power is equal to
Step by step
Solved in 2 steps
