A 1.50 kg block slides up a ramp that is inclined at 30 degrees above the horizontal. A constant horizontal force F is applied to the block as shown. Resolve all the forces intox-and-y components. 1 resolve all the forces into x-and y- components and draw the components on the diagram below
A 1.50 kg block slides up a ramp that is inclined at 30 degrees above the horizontal. A constant horizontal force F is applied to the block as shown. Resolve all the forces intox-and-y components. 1 resolve all the forces into x-and y- components and draw the components on the diagram below
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A 1.50 kg block slides up a ramp that is inclined at 30 degrees above the horizontal. A constant horizontal force F is applied to the block as shown. Resolve all the forces intox-and-y components. 1 resolve all the forces into x-and y- components and draw the components on the diagram below can you guys help me doing this.
Transcribed Image Text:A 1.50 kg block slides up a ramp that is inclined at 30.0° above the horizontal. A
constant horizontal force F is applied to the block as shown.
F-
30
The free-body diagram for this situation is shown below:
F stands for the horizontal force. It acts parallel to the floor.
n stands for the normal force. It acts perpendicular to the ramp.
f stands for the friction force. It acts parallel to the incline.
mg is the weight vector. It acts perpendicular to the floor.
(1) Resolve all the forces into x- and y-
components and draw the components on
the diagram below.
+y
n
F
F
30
"mg
mg
(2) In this box, write an equation for the sum of the force in the x- (3) In this box, write an equation for the sum of
the forces in the direction. You should have
an algebraic equation-variables only! Write
all components in terms of sine and cosine
direction. You should have an algebraic equation-variables
only!! Write all components in terms of sine and cosine
functions.
functions.
EEx =ma
全 FY_
=ma
my
+n - mg cos 300 s
F + Fcos 30
g sih 30"
1)
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