Answered: A (1.28×10^-5C) charge is moving at…

A (1.28×10^-5C) charge is moving at (5.63×10^7 m/s) perpendicular to a magnetic field of (8.91x10^-4T). What is the magnitude of magnetic force on the charge?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 5 T uniform magnetic field is oriented horizontally with respect to this page. A 3.0×10^ -6 C…

A: Field, B = 5 T Charge, q = 3×10-6 C Velocity, v = 1000 m/s Angle between field and velocity, θ = 90°

Q: A proton moving toward Earth at 8.86 ×107 m/s experiences a magnetic force of 7.52 ×10−16 N. What is…

A: Given data: The velocity of the proton towards earth is V=8.86x107 m/s. The magnitude of the…

Q: An electron with v = 320 m/s is moving through a region in which the magnetic field is B = 2.5 T. If…

Q: A magnetic field at the surface of a neutron star can reach 3.00 × 10^7T. What would be the radii of…

A: The magnitude of the magnetic field, B=3×107 T The speed of light, c=3×108 m/s

Q: A constant magnetic field of 100 µT is directed along the positive x-axis. If a 10 µC charge is…

A: Given data: Magnetic field B → = 100 μT i^ Change (q) = 10 μC Velocity v→ = 240×106 m/s j^ Required:…

Q: A charge Q = 6.2 x 10^-6 C, moves with a speed V = 4x10^6 i - 3x10^6 k and enters a Magnetic Field B…

Q: A particle with a charge of 5.82 µC moves through a magnetic field at a velocity of 50.0 m/s. If the…

A: Here the magnetic field is B=22.09 TExplanation:

Q: A physicist performing a sensitive measurement wants to limit the magnetic force on a moving point…

A: solution is given as

Q: A point charge moving in a magnetic field of 1.24 Tesla experiences a force of 0.615·10-11 N. The…

Q: An electron with momentum 5.60x10-19 kg∙m/s moves in circle of radius 5 m in uniform magnetic field.…

Q: A 6.5x10-5C charge is moving perpendicular to a magnetic field with a velocity of 15 m/s. If the…

A: Charge (q) = 6.5 × 10-5 C V = 15 m/s F = 6 N

Q: 8 μC charge travels from right to left through a magnetic field pointed out of the page. What is the…

Q: An electron travels at a speed of 9.5 x 106 m/s in a magnetic field of 1.16 x 10-3 T. As result of…

Q: A wire of length 0.863 m carries a current of 25.6 A. In the presence of a 0.693-T magnetic field,…

A: Write the expression for the magnetic force. Here, B is the magnetic field, I is the current, L is…

Q: current of 0.581A is flowing down a long straight wire. Current flows from left to right across the…

Q: A charged particle with a charge-to-mass ratio of lql/m = 5.7 × 10³ C/kg travels on a circular path…

A: Given : qm = charge to mass ratio = 5.7 * 108 C/ kg B = magnetic field = 0.76 T To be…

Q: A wire of length 0.579 m carries a current of 27.2 A. In the presence of a 0.612-T magnetic field,…

Q: proton is entering a region of a uniform magnetic field of strength (3.600x10^-3) T. The proton…

Q: An electron is traveling at 1 = (i + 3j - 5k) m/s and experience a magnetic field B = (2i+ 7j -6k)…

Q: A 15 mC charge has a velocity of m/s and is moving in a magnetic field T. What is the magnetic…

Q: A 2.59 x10² m long wire carries a current of 2.74 x 10³ A at an angle of 10.0° relative to Earth's…

A: The length of the wire, l=2.59×102 m The current flowing through the wire, i=2.74×103A The magnetic…

Q: Q.3: An electron moves through a uniform magnetic field given by B = (B,î + 3.0Bzj)T. At a…

Q: particle with a charge of -1.24 x 10-8 C moves with instantaneous velocity v (4.19 x 104 m/s)î +…

Q: A 5.47 C point charge is moving with a speed of 6.98 m/s. It is moving perpendicular to a magnetic…

A: Charge (q) = 5.47 C Speed (v) = 6.98 m/s Magnetic field (B) = 6.28 T

Q: given by v = (300 î + 400ĵ)km/s. Calculate the magnetic force acting on the electron. Q. 2: The…

Q: An electron moves at speed 8.00 × 10^5 m/s in a plane perpendicular to a cyclotron’s magnetic field.…

A: Given that --- speed of electron= 8.00 × 10^5 m/s magnetic force on the electron = 1.10 × 10^−13 N.…

Q: A 1500 kg car moves west along the equator. At this location Earth's magnetic field is 3.5 × 10^−5 T…

A: Given Data, Mass of the car (m)=1500 kg The Earth's Magnetic Field (B)=3.5 × 10−5 T Charge (q)=-2.5…

Q: See the attached figure for this problem. There is a charge of 6.24 x 10^-6 C moving at velocity…

A: Calculate the magnetic field due to the charge. Fm=qvBFm=(6.24×10−6 C)(8.62×105 m/s)(3 T)Fm=16.1 N

Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…

Q: A proton is travelling 2.4 x 10^9 m/s in a circular path with a magnetic force of 3.3 x 10^-10 N.…

Q: A particle with a charge of -1.24x10-8 C is moving with instantaneous velocity = (4.19×10¹ m/s)i +…

A: Given data : Charge on particle q = -1.24 × 10-8 C Velocity of charge particle v = (4.19 × 104…

Q: A proton moving at 5.50 x 106 m/s through a magnetic field of magnitude 1.77 T experiences a…

A: Given Speed , v = 5.50 × 106 m/s Magnetic field, B = 1.77 T Magnetic force, FB = 7.30 × 10-13 N

Q: AN ELECTRON MOVING 8 X 10^3m/s IN A 3.75 T MAGNETIC FIELD EXPERIENCES A MAGNETIC FORCE OF 2.5…

A: Given, magnitude of velocity of electron, v=8×103 m/s magnitude of magnetic field, B=3.75 T and…

Q: Here the charge is 3.09 x 10^-6 C, the magnetic field strength is 1.03 T and the electric field…

A: Charge is (q) = 3.09*10-6 CMagnetic field strength is (B) = 1.03 TElectric field strength is (E) =…

Q: a particle with a charge of -3.00x10^-5 C is moving with instantaneous velocity v=(400m/s)i + (-500…

Q: A particle with a charge of 0.9 C is moving at right angles to a uniform magnetic field with a…

A: Given that charge q=0.9 C magnetic field B=0.4T velocity v=700 m/s angle=90 deg.

Q: A small charged particle (mass = 240 µkg ; charge = - 480 µcoul) travels through a region of space…

Q: An proton moving at 2.00 x 10³ m/s and at an angle of 53° to a magnetic field experiences a magnetic…

Q: A proton moving at 4.00 × 106 m/s through a magnetic field of magnitude 1.70 T experiences a…

Q: At one instant, a proton is at the origin with a velocity (9 × 106,8 × 106, 4 × 106) m/s. At the…

Q: A particle with a charge of q = - 1.24 x 10-8C is moving with instantaneous velocity v=1.42 x 104…

Q: Problem 1: Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.25 μC…

A: Given value--- charge = 0.25 micro C. speed = 670 m/s. magnetic field = 8× 10-5 T. We have to…

Q: particle with charge 9.78 x 10^-6 C moves at 8.62 x 10^6 m/s through a magnetic field of strength…

Q: An electron is moving with an initial velocity of 7.09 x 10° m/s through a magnetic field. If the…

Q: If the magnetic field of the wire is 2.0x10-4 T and the electron moves at 9.0x106 m/s, what is the…

A: The magnitude of the force on the electron in a uniform magnetic field is given by F=qvBsinθFor…

Q: What is the force on an electron moving in the negative-z direction with a speed of 2.5 x 106 m/s in…

A: Given: The speed of the electron in the negative z-direction is v=2.5×106 m/s The magnetic field in…

Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

6.42x10^-1 N
1.14x10^-8 N
5.02x10^4 N
O 7.21x10^2 N

A (1.28×10^-5C) charge is moving at (5.63×10^7 m/s) perpendicular to a magnetic field of
(8.91x10^-4T). What is the magnitude of magnetic force on the charge?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A proton with a mass of 4.25 x10^26 kg travels at 5.69 x10^6 m/s perpendicular to a 2.35 T magnetic field. What is the radius of the circular path of the proton? An electron with a velocity of 8.45 x10^5 m/s is perpendicular to a magnetic field with a strength of 2.15. Calculate the radius of the curvature of an electron.
A force F = ( 6×10^-3 N)i - (4×10^-3 N)j - (8×10^-3 N)k is acting on a charge q = -2×10^-9 C moving inside a uniform magnetic field with a velocity v =(2×10^6m/s) i +(3×10^6m/s) j. Calculate the components of the magnetic field knowing that the x-component of the field is equal to zero.
A long straight wire has a current of 0.581A travelling through it. The wire is placed so that the current travels from left to right across the page. What is the magnitude of the magnetic field at a distance of 0.756m from the wire?
A particle with a charge of -1.2 x 10-8 C is moving with instantaneous velocityv = (4.2 x 104 m/s) i + (-3.8 x 104 m/s) j. What are the components of the force exerted on this particle by a magnetic field B = (1.4 T) i + (2.4 T) k ?
Calculate the magnetic force on an electron in the following cases. Provide your answers in component form (Here i, j, k denote the unit vectors for the x,y, and z directions, respectively.): a. A proton with velocity v = (1.20×104 i) m/s moving in a magnetic field of magnitude (0.7 k) T. Fx Fy F₂ Submit Answer Tries 0/10 = b. A proton with velocity v = (1.70×104 i) m/s moving in a magnetic field of magnitude (0.05 i + 0.7 j) T. Fx = Fy= F₂= Submit Answer Tries 0/10 c. A proton with velocity v = (1.50×104 i +5.00×10³ j) m/s moving in a magnetic field of magnitude (0.65 i + 0.85 k) T. Fx Fy= F₂ = Submit Answer Tries 0/10 Fy b. A proton with velocity v = (2.70×104 i +2.10×104 j+ 1.40×104 k) m/s moving in a magnetic field of magnitude (0.95 i -0.75 j + 0.2 k) T. Fx = = F₂ = Submit Answer Tries 0/10
A proton, that is accelerated from rest through a potential of 60 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. What is the proton's speed? Take т, — 1.67 х 10 27 kg and e - 1.6 x 10 19 с. B The speed, v - Units Select an answer The E-field between the plates is 1.3 x 106 N/C. What B-field is required so that the protons are not deflected? The magnetic field, B = Units Select an answer
A magnetic field has a magnitude of 0.0017 T, and an electric field has a magnitude of 6.0 x 10³ N/C. Both fields point in the same direction. A positive 1.7-μC charge moves at a speed of 4.2 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. Number i Units t
Chlorine ions whose masses are 5.8068*10^−26kg and 6.13842*10^(−26)kg. Ions are accelerated by voltage 10kV and they arrive perpendicular to the magnetic field which density is 1.8T. ions get into a circular orbit and collide after traveling in a semicircle to the observation board. How big is the distance between the chlorines on the observation board? charge is 1.60218*10−19coul
An electron moves with velocity v= (7.0i−6.0j)×10^4 m/s in a magnetic field B = (−0.80i+0.60j)T . a. Determine the x -component of the force on the electron. b. Determine the y -component of the force on the electron. c. Determine the z -component of the force on the electron.
A particle carries a charge of -3.35 x10^-8 C has a mass of 0.163 g. The particle has an initial northward velocity of 37069 m/s. What is the magnitude of the minimum magnetic field that will balance the earth's gravitational pull on the particle? Leave your answer in 1 decimal place.
A magnetic field has a magnitude of 1.5 ×10–3 T, and an electric field has a magnitude of 4.5 ×103 NC-1. Both fields point in the same direction. A positive 1.8 µC charge moves at a speed of 3.2 ×106 ms–1 in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge.
A charged particle moves into a region of uniform magnetic field, goes through half a circle, and then exits that region. The particle is either a proton or an electron (you must decide which). It spends 130 ns in the region. What is the magnitude of B? Give your answer in T. (mproton=1.672x1027 kg, melectron-9.1lx10-3! kg, e-1.602x10-19 C) OB