magnetic force

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter11: Magnetic Forces And Fields
Section: Chapter Questions
Problem 28P: An electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's...
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Calculate the magnetic force on an electron in the following cases. Provide your answers in component form (Here i, j, k denote the unit vectors for the x,y, and z directions, respectively.):
a. A proton with velocity v = (1.20×104 i) m/s moving in a magnetic field of magnitude (0.7 k) T.
Fx
Fy
F₂
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=
b. A proton with velocity v = (1.70×104 i) m/s moving in a magnetic field of magnitude (0.05 i + 0.7 j) T.
Fx
=
Fy=
F₂=
Submit Answer Tries 0/10
c. A proton with velocity v = (1.50×104 i +5.00×10³ j) m/s moving in a magnetic field of magnitude (0.65 i + 0.85 k) T.
Fx
Fy=
F₂ =
Submit Answer Tries 0/10
Fy
b. A proton with velocity v = (2.70×104 i +2.10×104 j+ 1.40×104 k) m/s moving in a magnetic field of magnitude (0.95 i -0.75 j + 0.2 k) T.
Fx
=
=
F₂ =
Submit Answer Tries 0/10
Transcribed Image Text:Calculate the magnetic force on an electron in the following cases. Provide your answers in component form (Here i, j, k denote the unit vectors for the x,y, and z directions, respectively.): a. A proton with velocity v = (1.20×104 i) m/s moving in a magnetic field of magnitude (0.7 k) T. Fx Fy F₂ Submit Answer Tries 0/10 = b. A proton with velocity v = (1.70×104 i) m/s moving in a magnetic field of magnitude (0.05 i + 0.7 j) T. Fx = Fy= F₂= Submit Answer Tries 0/10 c. A proton with velocity v = (1.50×104 i +5.00×10³ j) m/s moving in a magnetic field of magnitude (0.65 i + 0.85 k) T. Fx Fy= F₂ = Submit Answer Tries 0/10 Fy b. A proton with velocity v = (2.70×104 i +2.10×104 j+ 1.40×104 k) m/s moving in a magnetic field of magnitude (0.95 i -0.75 j + 0.2 k) T. Fx = = F₂ = Submit Answer Tries 0/10
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