A 1.2-kg block B is moving with velocity vo 2.5 m/s as it hits the 0.4-kg sphere A, which is at rest and hanging from a cord attached to O. Knowing that ,-0.6 between the block and horizontal surface and assuming elastic collision determine after the impact a) the maximum height, h, reached by the sphere, b) the distance, d, traveled by the block after collision.

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**Problem Statement (Educational Resource)**

*A 1.2 kg block B is moving with velocity \( v_B = 2.5 \, \text{m/s} \) as it hits the 0.4 kg sphere A, which is at rest and hanging from a cord attached to O. Knowing that \( \mu_k = 0.6 \) between the block and horizontal surface and assuming elastic collision determine after the impact:*

a) *the maximum height, \( h \), reached by the sphere,*

b) *the distance, \( d \), traveled by the block after the collision.*

**Explanation of the Graph/Diagram:**

The diagram included in the problem statement consists of the following components:

- Block B is shown moving horizontally towards the right with an initial velocity \( v_B = 2.5 \, \text{m/s} \).
- Sphere A is hanging from a cord attached at point O and is initially at rest (indicated by a horizontal line connected to point O).
- The block B and sphere A are depicted just before the collision.
- The diagram emphasizes the horizontal surface with a note mentioning kinetic friction \( \mu_k = 0.6 \).

The key elements of the diagram are labeled clearly:
- Block B is marked to show its mass (1.2 kg) and initial velocity (2.5 m/s).
- Sphere A is marked to indicate its mass (0.4 kg) and the cord from which it hangs.
- The distance \( d \), that we need to find, is the horizontal distance traveled by Block B after the collision.
- The maximum height \( h \), reached by Sphere A after the collision, is also to be determined.

The problem setup assumes an elastic collision scenario, which means that kinetic energy and momentum are conserved during the collision.
Transcribed Image Text:**Problem Statement (Educational Resource)** *A 1.2 kg block B is moving with velocity \( v_B = 2.5 \, \text{m/s} \) as it hits the 0.4 kg sphere A, which is at rest and hanging from a cord attached to O. Knowing that \( \mu_k = 0.6 \) between the block and horizontal surface and assuming elastic collision determine after the impact:* a) *the maximum height, \( h \), reached by the sphere,* b) *the distance, \( d \), traveled by the block after the collision.* **Explanation of the Graph/Diagram:** The diagram included in the problem statement consists of the following components: - Block B is shown moving horizontally towards the right with an initial velocity \( v_B = 2.5 \, \text{m/s} \). - Sphere A is hanging from a cord attached at point O and is initially at rest (indicated by a horizontal line connected to point O). - The block B and sphere A are depicted just before the collision. - The diagram emphasizes the horizontal surface with a note mentioning kinetic friction \( \mu_k = 0.6 \). The key elements of the diagram are labeled clearly: - Block B is marked to show its mass (1.2 kg) and initial velocity (2.5 m/s). - Sphere A is marked to indicate its mass (0.4 kg) and the cord from which it hangs. - The distance \( d \), that we need to find, is the horizontal distance traveled by Block B after the collision. - The maximum height \( h \), reached by Sphere A after the collision, is also to be determined. The problem setup assumes an elastic collision scenario, which means that kinetic energy and momentum are conserved during the collision.
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