A 1.00 M solution of fluoroacetic acid is 10.0% dissociated in water at a certain temperature. The dissociation is shown below. FCH2COOH + H2O = FCH2CO0- + H30* 1. Find the pOH of the solution. 14.00 13.00 2.59 1.00 None of the choices 2. What will be the corresponding dissociation constant, K, for the acid? 0.050 0.50 2.6 x 10-3 0.011 None of the choices 3. If this solution is diluted to 1.00 × 10-8 M, what will be the expected new pH? The pH will be around 8. None of the choices The pH will be around 7. The pH will be around 6. The pH will be around 3.

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A 1.00 M solution of fluoroacetic acid is 10.0% dissociated in water at a certain temperature. The dissociation is
shown below.
FCH2COOH + H2O = FCH2CO0- + H30*
1. Find the pOH of the solution.
14.00
13.00
2.59
1.00
None of the choices
2. What will be the corresponding dissociation constant, K, for the acid?
0.050
0.50
2.6 x 10-3
0.011
None of the choices
3. If this solution is diluted to 1.00 × 10-8 M, what will be the expected new pH?
The pH will be around 8.
None of the choices
The pH will be around 7.
The pH will be around 6.
The pH will be around 3.
Transcribed Image Text:A 1.00 M solution of fluoroacetic acid is 10.0% dissociated in water at a certain temperature. The dissociation is shown below. FCH2COOH + H2O = FCH2CO0- + H30* 1. Find the pOH of the solution. 14.00 13.00 2.59 1.00 None of the choices 2. What will be the corresponding dissociation constant, K, for the acid? 0.050 0.50 2.6 x 10-3 0.011 None of the choices 3. If this solution is diluted to 1.00 × 10-8 M, what will be the expected new pH? The pH will be around 8. None of the choices The pH will be around 7. The pH will be around 6. The pH will be around 3.
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