A 1.00-L flask is filled with 1.00 moles of H2 and 2.00 moles of 2. The value of the equilibrium constant for the reaction of hydrogen and iodine reacting to form hydrogen iodide is 16.0 under the given conditions. What are the equilibrium concentrations of H2, 2, and HI? H2(g)+l2(g) =2HI(g) O IH2] = 0.155 M [12] = 1.155 M [H]] = 1.690 M O IH2] = 0.155 M [12] = 0.255 M [Hi] = 0.690 M O (H2) = 0.055 M [12] = 1.155 M [Hi] = 2.690 M O (H2] = 0.655 M [12] = 0.155 M [H]] = 1.690 M
A 1.00-L flask is filled with 1.00 moles of H2 and 2.00 moles of 2. The value of the equilibrium constant for the reaction of hydrogen and iodine reacting to form hydrogen iodide is 16.0 under the given conditions. What are the equilibrium concentrations of H2, 2, and HI? H2(g)+l2(g) =2HI(g) O IH2] = 0.155 M [12] = 1.155 M [H]] = 1.690 M O IH2] = 0.155 M [12] = 0.255 M [Hi] = 0.690 M O (H2) = 0.055 M [12] = 1.155 M [Hi] = 2.690 M O (H2] = 0.655 M [12] = 0.155 M [H]] = 1.690 M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![A 1.00-L flask is filled with 1.00 moles of H2 and 2.00 moles of 12. The value of the equilibrium constant for the reaction of hydrogen and iodine reacting to form hydrogen iodide is 16.0 under the given
conditions. What are the equilibrium concentrations of H2, I2, and HI?
H2(g)+l2(g) =2HI(g)
O IH21 = 0.155 M
[12] = 1.155 M
[H] = 1.690 M
O (H2] = 0.155 M
[12] = 0.255 M
[Hi] = 0.690 M
O H2) = 0.055 M
[12] = 1.155 M
[Hi] = 2.690 M
O (H2] = 0.655 M
[12] = 0.155 M
[H]] = 1.690 M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcfef55d1-e74e-4acc-a65e-b6e34bf1c85d%2Fb9d79ca0-c6a5-4346-ac35-140389f9d007%2Fuv7n4u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 1.00-L flask is filled with 1.00 moles of H2 and 2.00 moles of 12. The value of the equilibrium constant for the reaction of hydrogen and iodine reacting to form hydrogen iodide is 16.0 under the given
conditions. What are the equilibrium concentrations of H2, I2, and HI?
H2(g)+l2(g) =2HI(g)
O IH21 = 0.155 M
[12] = 1.155 M
[H] = 1.690 M
O (H2] = 0.155 M
[12] = 0.255 M
[Hi] = 0.690 M
O H2) = 0.055 M
[12] = 1.155 M
[Hi] = 2.690 M
O (H2] = 0.655 M
[12] = 0.155 M
[H]] = 1.690 M
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