a = [1, 2,5] b = [1, 2, 3] ind=a.index(5) print(b[ind]) a = [1, 2, 5] b = [1, 2, 3] y=0 for x in a: y +=x b.append(y) print(b) a = (1, 2, 5) b = [1,2,3] y=0 for x in a: y +=x a.append(y) print(a)
a = [1, 2,5] b = [1, 2, 3] ind=a.index(5) print(b[ind]) a = [1, 2, 5] b = [1, 2, 3] y=0 for x in a: y +=x b.append(y) print(b) a = (1, 2, 5) b = [1,2,3] y=0 for x in a: y +=x a.append(y) print(a)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Give the output for the following Code (Python)
![a = [1, 2, 5]
b = [1, 2, 3]
ind=a.index(5)
print(b[ind])
= [1, 2, 5]
a
b = [1, 2, 3]
y=0
for x in a:
y +=x
b.append(y)
print(b)
a = (1, 2, 5)
= [1, 2, 3]
b
y=0
for x in a:
y +=x
a.append(y)
print(a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdefdb26c-a9ef-43ac-8bc3-8ded37bcc233%2Ffae53193-310c-4464-a9f8-5d6f2cc9f725%2Fwn9xltm_processed.png&w=3840&q=75)
Transcribed Image Text:a = [1, 2, 5]
b = [1, 2, 3]
ind=a.index(5)
print(b[ind])
= [1, 2, 5]
a
b = [1, 2, 3]
y=0
for x in a:
y +=x
b.append(y)
print(b)
a = (1, 2, 5)
= [1, 2, 3]
b
y=0
for x in a:
y +=x
a.append(y)
print(a)
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