A 0.500-kg metal rod carrying a current of 20.0 A glides on two horizontal rails 1.00 m apart. What vertical magnetic field is required to keep the rod moving at a constant speed if the coefficient of kinetic friction between the rod and rails is 0.200? Give your answer in mT. (g=9.80 m/s?)
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Q: See the attached figure for this problem. There is a charge is 9.61 x 10^-6 C, the magnetic field…
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- Calculate the magnitude and direction of the magnetic force on an electron moving with a velocity of 5.0 × 104 (?̂) m/s in a uniform magnetic field of 0.67 (?̂) T.An particle with charge -e is fired into a magnetic field B = 2.0 mT. The velocity of the particle is 7.1 x 10 m/s and is perpendicular to the magnetic field. What is the magnitude of the force this particle will experience? Note that 1 mT = 10-³ T. F= N The particle's radius of curvature is 0.030 meters. What is its mass? Note that you can enter exponential notation as x.yzEq to represent xyz x 109 (for example, 1.23E-24 can be entered for 1.23 x 10-24), m= kgSee the attached figure for this problem. A charge of 7.69 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 4.44 T directed into the screen and an electric field of strength 5.51 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed? 3.72E+04 m/s 1.24E+05 m/s 9.92E+04 m/s 6.20E+04 m/s
- A wire carrying a 28.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.25 N force on the 6.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet?What is the strength of the magnetic field at the center of a circular loop of wire of diameter 9.48 cm when a current of 5.91 A flows in the wire? (μ0 = 4π × 10-7 T ∙ m/A) (Use π = 3.14). Express answers in milliTeslas.A particle of mass 9.02 g and charge 63.5 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is -9.8 m/s² without falling. The velocity of the particle is a constant 18.27 km/s, which is perpendicular to the magnetic field. What, then, is the magnetic field? Number ( i Ĵ+ i k) Units
- Option 2: a. An electron is moving at a speed of 4.45 x 105 m/s from north to south in a magnetic field that runs from [NE] to [SWJ. If the magnetic force balances the gravitational force on the electron, determine the strength of the magnetic field. b. Now consider a 50.0 cm long wire with a mass of 60.0 g that carries a current of 15.0 A from north to south. The uniform magnetic field is perpendicular to the above- mentioned wire. What the minimum magnetic field strength and direction that will balance the weight of the wire?A 0.200-kg metal rod carrying a current of 10.0 A glides on two horizontal rails 0.500 m apart. What vertical magnetic field is required to keep the rod moving at a constant speed if the coefficient of kinetic friction between the rod and rails is 0.100?A force F = ( 6×10^-3 N)i - (4×10^-3 N)j - (8×10^-3 N)k is acting on a charge q = -2×10^-9 C moving inside a uniform magnetic field with a velocity v =(2×10^6m/s) i +(3×10^6m/s) j. Calculate the components of the magnetic field knowing that the x-component of the field is equal to zero.
- A wire carries I1=7.96 A current along the x-axis, and another wire carries an I2=1.15 A current along the y-axis, as shown in the figure below. What is the magnitude of magnetic field at point at x = 0.400m , y = 0.300m? The magnitude of the net magnetic field at point P is?(Note : mu T=10^ -6 T) .A particle of charge = +7.9 nC and mass = 5 micro-gram) moves with a velocity V = 8.8 i km/s in a region where the magnetic field is B = 6.8 j+ 7 k mī. What is the magnitude of the force on the particle due to the magnetic field? Write your answer in nano-newtons.A wire of a certain length is carrying a current, I of 2.0 A. It is placed at an angle of 60º with respect to a 0.20-T magnetic field. If the wire experiences a force of 0.40 N, what is the length, l of the wire? Hint: F = B. I. l. sin θ , Solve for l(the length of the wire). Group of answer choices A) 1.15 m B) 11.2 m C) 0.9 m D) 1.6 m Please show how to solve and provide explanations. I am struggling to understand this section of physics and your help is greatly appreciated!