A 0.500 g sample consisting of Na2CO3, NaHCO3, and inert materials was dissolved in sufficient water to give 250.0 mL of solution. A 25.00 mL aliquot of this solution was boiled with 50.00 mL of 0.01255 M HCI. Titration of the excess HCI to a phenolphthalein endpoint required 2.34 ml of 0.01063 M NaOH. The carbonate species in the second 25.00 mL aliquot was precipitated with an excess of BaCl2 and treated with 25.00 mL of the NaOH. Titration of the excess base required 7.63 mL of the standard acid. Calculate % Na,CO3 and NaHCO3 in the sample.
A 0.500 g sample consisting of Na2CO3, NaHCO3, and inert materials was dissolved in sufficient water to give 250.0 mL of solution. A 25.00 mL aliquot of this solution was boiled with 50.00 mL of 0.01255 M HCI. Titration of the excess HCI to a phenolphthalein endpoint required 2.34 ml of 0.01063 M NaOH. The carbonate species in the second 25.00 mL aliquot was precipitated with an excess of BaCl2 and treated with 25.00 mL of the NaOH. Titration of the excess base required 7.63 mL of the standard acid. Calculate % Na,CO3 and NaHCO3 in the sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A 0.500 g sample consisting of Na2CO3, NaHCO3, and inert materials was dissolved in sufficient water to give 250.0 mL of solution. A 25.00 mL aliquot of this solution was boiled with 50.00 mL of 0.01255 M HCI. Titration of the excess HCI to a phenolphthalein endpoint required 2.34 ml of 0.01063 M NaOH. The carbonate species in the second 25.00 mL aliquot was precipitated with an excess of BaCl2 and treated with 25.00 mL of the NaOH. Titration of the excess base required 7.63 mL of the standard acid. Calculate % Na,CO3 and NaHCO3 in the sample.
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