An analytical chemist is titrating 230.5 mL of a 0.1500M solution of isopropylamine ((CH3), CHNH₂) with a 0.4100M solution of HNO3. The pK, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 60.1 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places.
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
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