An analytical chemist is titrating 230.5 mL of a 0.1500M solution of isopropylamine ((CH3), CHNH₂) with a 0.4100M solution of HNO3. The pK, of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 60.1 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Titration Problem: Calculating pH after Addition of HNO₃ Solution**

An analytical chemist is titrating 230.5 mL of a 0.1500 M solution of isopropylamine ((CH₃)₂CHNH₂) with a 0.4100 M solution of HNO₃. The \( pK_b \) of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 60.1 mL of the HNO₃ solution to it.

**Note for advanced students:** You may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added.

**Instructions and Assumptions:**
1. The final volume is considered to be the sum of the volumes of both solutions mixed.
2. Round your answer to 2 decimal places.

*Note: This tutorial assumes an understanding of chemical equilibrium, acid-base reactions, and logarithmic calculations.*

**Graph and Diagram Explanation:** 
There are no graphs or diagrams accompanying this problem. The solution requires algebraic and logarithmic calculations involving molarity and equilibrium constants. 

For assistance, refer to foundational concepts on acid-base titrations, the Henderson-Hasselbalch equation, and logarithmic conversions.
Transcribed Image Text:**Titration Problem: Calculating pH after Addition of HNO₃ Solution** An analytical chemist is titrating 230.5 mL of a 0.1500 M solution of isopropylamine ((CH₃)₂CHNH₂) with a 0.4100 M solution of HNO₃. The \( pK_b \) of isopropylamine is 3.33. Calculate the pH of the base solution after the chemist has added 60.1 mL of the HNO₃ solution to it. **Note for advanced students:** You may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added. **Instructions and Assumptions:** 1. The final volume is considered to be the sum of the volumes of both solutions mixed. 2. Round your answer to 2 decimal places. *Note: This tutorial assumes an understanding of chemical equilibrium, acid-base reactions, and logarithmic calculations.* **Graph and Diagram Explanation:** There are no graphs or diagrams accompanying this problem. The solution requires algebraic and logarithmic calculations involving molarity and equilibrium constants. For assistance, refer to foundational concepts on acid-base titrations, the Henderson-Hasselbalch equation, and logarithmic conversions.
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