Solve it asap A 0.28-kg block on a horizontal frictionlesssurface is attached to an ideal masslessspring whose spring constant is 500 N/m.The block is pulled from its equilibriumposition at x = 0 m to a displacement x =%3D+0.080 m and is released from rest. Theblock then executes simple harmonicmotion along the horizontal x-axis. Whenthe displacement is x = -0.052 m, find the%3Dacceleration of the block. ?109

Concept: The Expression for Simple harmonic Motion of the spring is expressed as a=-ω2x…

A 0.28-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 500 N/m. The block is pulled from its equilibrium position at x = 0 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = -0.052 m, find the acceleration of the block. ?109

A 0.28-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 500 N/m. The block is pulled from its equilibrium position at x = 0 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = -0.052 m, find the acceleration of the block. ?109