Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
A 0.25 kg particle moves in an xy plane according to -3.7 1542-43 and y(t) = 25 + 7t9t2, with x and y in x(t) meters and in seconds. NOTE: Express your answers in terms of t. (a) Find an expression at time t < 0.35 s for the magnitude of the net force on the particle (in newtons). F = √36 ²+20.25 (b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X

A 0.25 kg particle moves in an xy plane according to -3.7 1542-43 and y(t) = 25 + 7t9t2, with x and y in x(t) meters and in seconds. NOTE: Express your answers in terms of t. (a) Find an expression at time t < 0.35 s for the magnitude of the net force on the particle (in newtons). F = √36 ²+20.25 (b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X

icon
Related questions
Question
(b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X (c) Find an expression at time t < 0.35 s for the angle of the particle's direction of travel (in radians). 0 0.83 X
Transcribed Image Text:(b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X (c) Find an expression at time t < 0.35 s for the angle of the particle's direction of travel (in radians). 0 0.83 X
A 0.25 kg particle moves in an xy plane according to -3.7 x(t) meters and in seconds. 15+2t 1524t3 and y(t) = 25 + 7t9t2, with x and y in NOTE: Express your answers in terms of t. (a) Find an expression at time t < 0.35 s for the magnitude of the net force on the particle (in newtons). F = √36 t2 +20.25 (b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X
Transcribed Image Text:A 0.25 kg particle moves in an xy plane according to -3.7 x(t) meters and in seconds. 15+2t 1524t3 and y(t) = 25 + 7t9t2, with x and y in NOTE: Express your answers in terms of t. (a) Find an expression at time t < 0.35 s for the magnitude of the net force on the particle (in newtons). F = √36 t2 +20.25 (b) Find an expression at time t < 0.35 s for the angle (relative to the positive direction of the x axis) of the net force on the particle (in radians). 0 = 3.78 X
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer