A 0.200 kg mass attached to the end of a spring causes it to stretch 5.0 cm. If another 0.200 kg mass is added to the spring, the total amount of stretch of the spring will be A) the same. B) one-half as much. C) twice as much. D) 3 times as much. E) 4 times as much.

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Question:**

A 0.200 kg mass attached to the end of a spring causes it to stretch 5.0 cm. If another 0.200 kg mass is added to the spring, the total amount of stretch of the spring will be:

A) the same.  
B) one-half as much.  
C) twice as much.  
D) 3 times as much.  
E) 4 times as much.  

**Answer Options:**

- ○ A
- ○ B
- ○ C
- ○ D
- ○ E

**Explanation:**

This problem involves concepts of Hooke's Law, which states that the force exerted by a spring is directly proportional to the amount it is stretched, assuming the elastic limit is not exceeded. When an additional 0.200 kg mass is added, the force on the spring doubles, leading to a corresponding increase in stretch distance. This means that the stretch should be twice as much compared to the original stretch with one 0.200 kg mass.
Transcribed Image Text:**Question:** A 0.200 kg mass attached to the end of a spring causes it to stretch 5.0 cm. If another 0.200 kg mass is added to the spring, the total amount of stretch of the spring will be: A) the same. B) one-half as much. C) twice as much. D) 3 times as much. E) 4 times as much. **Answer Options:** - ○ A - ○ B - ○ C - ○ D - ○ E **Explanation:** This problem involves concepts of Hooke's Law, which states that the force exerted by a spring is directly proportional to the amount it is stretched, assuming the elastic limit is not exceeded. When an additional 0.200 kg mass is added, the force on the spring doubles, leading to a corresponding increase in stretch distance. This means that the stretch should be twice as much compared to the original stretch with one 0.200 kg mass.
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