A 0.2-C particle of mass 0.25 kg is released from rest and acted on by two forces: its weight and the electric force from to an upward 9 N/C uniform electric field. Calculate the magnitude and direction of its acceleration, taking upward to be positive direction... M/S2
Q: A proton is projected in the positive x direction into a region of uniform electric field E = (-6.90…
A: The uniform electric field is, E=-6.9×105i^ N/C The distance traveled by a proton is, d=6.30…
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Q: the strength of the electric field
A: The expression for the electric field is given as,
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A: Recall F=Eq ax=Eq/mpNow vx=axtAnd velocity along y axis will remain constant.
Q: Q2.A proton is projected in the positive x direction into a region of a uniform electric fieldE =…
A: Given : E→=-6.00 x 105i^ N/C m = 1.67 x 10-27 q = 1.6 x 10-19
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Q: LA-1 A proton is released at rest in an electric field E-450N/C. Neglect the effect of the weight of…
A: Given that Initial velocity of the proton (v1) =0 Final velocity is (v2) =1.50x106m/s Electric field…
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Q: simple and common technique for accelerating electrons is shown in the figure below, where there is…
A: Solution: Given: m = mass of electron = 9.11 x 10-31 kg e = charge on electron = -1.60 x 10-19 C E =…
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Q: An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C,…
A: Given data:Electric field E=1.25KN/c E=1.25×103N/c Time t=20 ns t=20×10-9 s
Q: 1) An electron is released from rest in a weak electric field given by -2.9 x 10-10 N/C Ĵ. After the…
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- A proton is projected in the positive x direction into a region of uniform electric field E = (-5.30 x 105) i N/C at t = 0. The proton travels 6.40 cm as it comes to rest. (a) Determine the acceleration of the proton. 0.9638e7 X magnitude How..do.you find the acceleration of an object if you know the net force that acts on it? m/s² direction --Select- (b) Determine the initial speed of the proton. 0.351e7 X magnitude The electric field is constant, so the force is constant, which means the acceleration will be constant. m/s direction -Select-- (c) Determine the time interval over which the proton comes to rest. 0.3640 You appear to have calculated the time correctly using your incorrect results from parts (a) and (b). sa) A particle with a mass of 0.003 grams and a charge of-5x10°C was placed in an upward electric field with a magnitude of 350,000 N/C. What is the direction of the acceleration that the particle will feel? 22 b) What is the magnitude of the acceleration that the particle will feel? b) If it is in the field for 0.25 seconds, how far will it go?A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.
- A proton is shot in a region with a velocity 2×106 m/s along positive x- .direction An electric field É = -(120 kN/C)í exists in the region. (1kN = 1000 N) .mass of proton = 1.67x1027 kg %3D How far does the proton travel along the x-axis before reaching its turning ?point...A 2-kg mass holds a total charge of -2 C. Near the surface of a planet where g = 10 N/kg, we see it hovering. What must be the magnitude and direction of the electric field in which the object resides? A. 10 N/C, upwards B. 10 N/C, downwards C. 20 N/C, upwards D. 20 N/C, downwards E. 5 N/C, upwards F. 5 N/C, downwards (Make sure you understand the specific chain of logic to determine the direction of the electric field. The answer is B, why?
- Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 310 N/C. (a) What is the magnitude of the acceleration of the electron (in m/s²)? 5.14e13 X How is the electric force related to the electric field? How is the acceleration related to the force? What m/s² -9 (b) The electron is initially at rest. What is its speed (in m/s) after 8.50 x 10 s? m/sAn electron is accelerated by a constant electric field of magnitude 270 N/C. (a) Find the acceleration of the electron. |m/s² (b) Use the equations of motion with constant acceleration to find the electron's speed after 9.00 x 10° s, assuming it starts from rest. m/s