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A proton is projected in the positive x direction into a region of uniform electric field E = (-5.30 x 105) N/C at t = 0. The proton travels 6.40 cm as it comes to rest. (a) Determine the acceleration of the proton. 0.9638e7 X How..do.you find the acceleration of an object if you know the net force that acts on it? m/s² magnitude direction --Select- (b) Determine the initial speed of the proton. 0.351e7 X The electric field is constant, so the force is constant, which means the acceleration will be constant. m/s direction -Select-- magnitude (c) Determine the time interval over which the proton comes to rest. 0.3640 X You appear to have calculated the time correctly using your incorrect results from parts (a) and (b). s

A proton is projected in the positive x direction into a region of uniform electric field E = (-5.30 x 105) N/C at t = 0. The proton travels 6.40 cm as it comes to rest. (a) Determine the acceleration of the proton. 0.9638e7 X How..do.you find the acceleration of an object if you know the net force that acts on it? m/s² magnitude direction --Select- (b) Determine the initial speed of the proton. 0.351e7 X The electric field is constant, so the force is constant, which means the acceleration will be constant. m/s direction -Select-- magnitude (c) Determine the time interval over which the proton comes to rest. 0.3640 X You appear to have calculated the time correctly using your incorrect results from parts (a) and (b). s

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### Physics Problem: Proton in a Uniform Electric Field A proton is projected in the positive x direction into a region of uniform electric field \(\vec{E} = (-5.30 \times 10^5 \vec{i}) \ \text{N/C}\) at \(t = 0\). The proton travels 6.40 cm as it comes to rest. #### (a) Determine the acceleration of the proton. - **Magnitude:** - Attempt: \(0.9638 \times 10^7 \ \text{m/s}^2\) - Feedback: How do you find the acceleration of an object if you know the net force that acts on it? - **Direction:** - Selection needed #### (b) Determine the initial speed of the proton. - **Magnitude:** - Attempt: \(0.351 \times 10^7 \ \text{m/s}\) - Feedback: The electric field is constant, so the force is constant, which means the acceleration will be constant. - **Direction:** - Selection needed #### (c) Determine the time interval over which the proton comes to rest. - **Time Interval:** - Attempt: \(0.3640 \ \text{s}\) - Feedback: You appear to have calculated the time correctly using your incorrect results from parts (a) and (b). ### Explanation of the Steps Involved: 1. **Acceleration Calculation:** - To find the acceleration (\(a\)), use the equation derived from Newton's second law: \[ F = ma \] Here, \(F\) is the force on the proton due to the electric field \( \vec{E} \), and \(m\) is the mass of the proton. The force \( F \) can be calculated as: \[ F = qE \] where \( q \) is the charge of the proton (\(1.602 \times 10^{-19} \ \text{C}\)). Therefore: \[ a = \frac{F}{m} = \frac{qE}{m} \] 2. **Initial Speed Calculation:** - To find the initial speed (\(v_0\)), use the kinematic equation: \[ v_f^2 = v_0^2
Transcribed Image Text:### Physics Problem: Proton in a Uniform Electric Field A proton is projected in the positive x direction into a region of uniform electric field \(\vec{E} = (-5.30 \times 10^5 \vec{i}) \ \text{N/C}\) at \(t = 0\). The proton travels 6.40 cm as it comes to rest. #### (a) Determine the acceleration of the proton. - **Magnitude:** - Attempt: \(0.9638 \times 10^7 \ \text{m/s}^2\) - Feedback: How do you find the acceleration of an object if you know the net force that acts on it? - **Direction:** - Selection needed #### (b) Determine the initial speed of the proton. - **Magnitude:** - Attempt: \(0.351 \times 10^7 \ \text{m/s}\) - Feedback: The electric field is constant, so the force is constant, which means the acceleration will be constant. - **Direction:** - Selection needed #### (c) Determine the time interval over which the proton comes to rest. - **Time Interval:** - Attempt: \(0.3640 \ \text{s}\) - Feedback: You appear to have calculated the time correctly using your incorrect results from parts (a) and (b). ### Explanation of the Steps Involved: 1. **Acceleration Calculation:** - To find the acceleration (\(a\)), use the equation derived from Newton's second law: \[ F = ma \] Here, \(F\) is the force on the proton due to the electric field \( \vec{E} \), and \(m\) is the mass of the proton. The force \( F \) can be calculated as: \[ F = qE \] where \( q \) is the charge of the proton (\(1.602 \times 10^{-19} \ \text{C}\)). Therefore: \[ a = \frac{F}{m} = \frac{qE}{m} \] 2. **Initial Speed Calculation:** - To find the initial speed (\(v_0\)), use the kinematic equation: \[ v_f^2 = v_0^2
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