A 0.04336 g sample of gas occupies 10.0 mL at 293.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound? Draw the Lewis structure of the compound. molecular formula: Select Draw Rings More C Br F Cl G 45 Erase Q2 Q

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A 0.04336 g sample of gas occupies 10.0 mL at 293.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl.

What is the molecular formula of the compound?

molecular formula:
Draw Lewis structure 
### Determining the Molecular Formula of a Compound

A 0.04336 g sample of gas occupies 10.0 mL at 293.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% Carbon (C) and 74.695% Chlorine (Cl).

**Question**:
What is the molecular formula of the compound?

**Answer**:
To find the molecular formula, first, determine the moles of each element based on their percentages and then use that to find the empirical and molecular formulas.

#### Molecular Formula Calculation
Please enter the molecular formula in the box below:

**Molecular Formula**:
```
____________________
```

#### Lewis Structure Drawing
Next, we need to draw the Lewis structure of the compound.

Use the provided drawing tools to depict the molecule. The available tools on the interface include:

- Single bond (`/`)
- Double bond (`//`)
- Triple bond (`///`)
- Elements: Carbon (C), Bromine (Br), Fluorine (F), Chlorine (Cl)

To draw the structure:
1. Select the type of bond you want to use.
2. Select the element.
3. Place them accordingly on the drawing board.

You can also use the following functions to refine your drawing:
- Undo
- Redo
- Zoom in and out

Make sure your drawing is accurate and represents the correct molecular structure.

---

This corresponds to the given image which has a text-based question on the molecular formula of a compound and a section to draw its Lewis structure using the provided tools.
Transcribed Image Text:### Determining the Molecular Formula of a Compound A 0.04336 g sample of gas occupies 10.0 mL at 293.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% Carbon (C) and 74.695% Chlorine (Cl). **Question**: What is the molecular formula of the compound? **Answer**: To find the molecular formula, first, determine the moles of each element based on their percentages and then use that to find the empirical and molecular formulas. #### Molecular Formula Calculation Please enter the molecular formula in the box below: **Molecular Formula**: ``` ____________________ ``` #### Lewis Structure Drawing Next, we need to draw the Lewis structure of the compound. Use the provided drawing tools to depict the molecule. The available tools on the interface include: - Single bond (`/`) - Double bond (`//`) - Triple bond (`///`) - Elements: Carbon (C), Bromine (Br), Fluorine (F), Chlorine (Cl) To draw the structure: 1. Select the type of bond you want to use. 2. Select the element. 3. Place them accordingly on the drawing board. You can also use the following functions to refine your drawing: - Undo - Redo - Zoom in and out Make sure your drawing is accurate and represents the correct molecular structure. --- This corresponds to the given image which has a text-based question on the molecular formula of a compound and a section to draw its Lewis structure using the provided tools.
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