A 0.015-kg bullet is fired into a stationary block of wood of mass of 4.8 kg. The relative speed of the bullet with respect to the wood is zero after collision (The bullet becomes embedded on the block of wood). If the speed of the bullet before collision is 468 m/s, what is the kinetic energy of the bullet-plus-wood combination right after the collision? AsSsume no change in the potential energy of the system before and after the collision. Express your answer in two decimal places, in Joules.

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A 0.015-kg bullet is fired into a stationary block of wood of mass of 4.8 kg. The
relative speed of the bullet with respect to the wood is zero after collision (The bullet
becomes embedded on the block of wood). If the speed of the bullet before collision is
468 m/s, what is the kinetic energy of the bullet-plus-wood combination right after
the collision? Assume no change in the potential energy of the system before and
after the collision. Express your answer in two decimal places, in Joules.
Transcribed Image Text:A 0.015-kg bullet is fired into a stationary block of wood of mass of 4.8 kg. The relative speed of the bullet with respect to the wood is zero after collision (The bullet becomes embedded on the block of wood). If the speed of the bullet before collision is 468 m/s, what is the kinetic energy of the bullet-plus-wood combination right after the collision? Assume no change in the potential energy of the system before and after the collision. Express your answer in two decimal places, in Joules.
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