A ball of mass 500 g swings on the end of a 70 cm long string and collides with a 2.5 kg block as shown. Assume that the collision is perfectly elastic. a) What is the speed of the block immediately after the collision? b) How high does the ball rise after the collision?
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- A ball of mass m moving with a speed v collides elastically with a stationary ball of mass 3m. During the collision the total kinetic energy decreases and then returns to its original value. Which of the following statements correctly describes the system when the kinetic energy reaches a minimum? * 5 The speeds of the two balls are equal The kinetic energies of the two balls are equal The momentum of each ball is the same The potential energy stored in the system equals the total kinetic energy O The total momentum of the system is a minimumWhen no energy is lost to thermal modes in a collision, the coefficient of restitution is e = 1. This represents the ideal golfing equipment. The legal maximum is e = 0.83. A 200-g clubhead moving at 88 mph strikes a golf ball. The mass of the golf ball is 45 g. Determine the amount of energy that winds up as KEclubhead, KEball, and Etherm for e = 0.83. Round the final answer to two decimal places.= 4.05 kq is released from . It makes a head-on elastic collision at B with a block of Consider a frictionless track as shown in the figure below. A block of mass m 13.0 kg that is initially at rest. Calculate the maximum height to which m, rises after the collision mass m2 m тy 5.00 m т2 B
- Bullet of mass 105 grams, hits the stationary block of mass 15,190g (originally frictionless surface) and embeds in it. The block then enters a rough surface (coefficient of friction= 0.30) by a distance of 9.0 meters, before coming to stop. Find the speed of the bullet when it hits the block. Use g = 9.8 m/s2 and state your answer in m/s to the nearest tenth of m/s.A teacher attending a meeting decided to check what would happen with kinetic mercy if she changed the momentum. She decided to conduct an experiment using a dynamics cart. The student measured the speed of the cart as she released it from inclined surfaces with different slopes. She was able to increase the momentum by a factor of 17. By what factor did the kinetic energy change.A 0.018-kg bullet is fired into a stationary block of wood of mass of 5.1 kg. The relative speed of the bullet with respect to the wood is zero after collision (The bullet becomes embedded on the block of wood). If the speed of the bullet before collision is 475 m/s, what is the kinetic energy of the bullet-plus-wood combination right after the collision? Assume no change in the potential energy of the system before and after the collision. Express your answer in two decimal places, in Joules.
- A 7.3kg bowling ball collides with a 1.5kg pin that was at rest. Before the collision the ball speed is +6.0 m/s. After the collision, the speed of the ball is +5.4 m/s. What is the speed of the pin after the crash?A 7,300-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 8 m/s. Compute how much kinetic energy was "lost" in this inelastic collision. answer using J (JOULE)An object of mass 2kg collided with an object of mass 1kg that is at rest. After the collision the 2kg object has a speed of 2m/s and the 1 kg object has a speed of 8m/s. What is the initial speed of the 2kg object ?
- A 1500kg sport car is moving westbound at 20m/s on a level road when it collided with a 4000kg truck driving east on the same road at 15m/s. The two vehicles remain locked together after the collision.b) what is the total kinetic energy of the two vehicles just after collisionA truck (m=5000 kg) initially moving at 5 m/s slams into the back of a car (m=1,000 kg) that is sitting at an intersection. The bumpers lock, and the two vehicles move off together. In the instant right after the collision, what is the speed of this wreckage? How much energy is dissipated? v = 5 m/s 100-160 m=5,000 kg m=1,000 kgAnswer question 7