99. A 95% confidence interval for the mean price of textbooks at UCLA in the spring quarter of 2010,based on a random sample taken by statistician David Diez, was ($58.30,$86.14). To obtain thisinterval, he multiplied the standard error by 2.04, which was the value of t*. What would havebeen the effect if he had multiplied the standard error by 1.70 instead? Choose the best answer.(a) The confidence interval would have been wider.(b) The confidence interval would have been narrower.(c) The confidence level would have been higher.(d) The confidence level would have been lower.(e) Answers a and c are both correct.(f) Answers b and d are both correct.

The 95% confidence interval for the mean price of textbooks, will signify that, with 95% confidence…

Answered: 99. A 95% confidence interval for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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12
The following data were collected during a study of consumer buying patterns: Observation Observation 1 11 30 77 8. 23 78 77 9 10 69 44 82 10 19 70 34 84 11 23 87 47 92 12 19 90 42 93 13 32 91 32 79 b. Obtain a linear regression line for the data. (Round your intermediate calculations and final answers to 3 decimal places.) y= c. What percentage of the variation is explained by the regression line? (Do not round intermediate calculations. Round your answer to the nearest whole percent. Omit the "%" sign in your response.) Approximately % of the variation in the dependent variable is explained by the independent variable. d. Use the equation determined in part b to predict the expected value of y for x= 43. (Round your intermediate calculations and final answers to 3 decimal places.) %3D
Suppose that for a test of proportion we have :p=0.5 and . The test statistic z=1.53 and the p-value is reported as P-value = 0.063. Find the error in the reasoning. This is a right-tailed test so the P-value should be 0.9370. This is a two-tailed test so the P-value should be 0.126. The P-value should have been calculated using the studentâ s t-distribution. There is no error in the reasoning. None of these.
A standardized math test of fifth grade students produces a mean ?μ = 100 with a ?σ = 18. A sample of n = 36 students participated in "boost" training for their math skills. The sample M = 104 with S = 24. Did this "boost" training significantly improve students' math performance? Use ?α = .01.
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
A sample of 134 motels is selected from a large urban area and the price for a night of lodging for a single room was determined for each motel. The mean rate is computed to be $87 and the standard deviation is $14. One motel charged $57 per night which is the 13th percentile. Another motel charged $118 per night which is the 75th percentile. Step 3 of 4 : One of the motels was 1.3 standard deviations below the mean, what is the price of a single room at the motel? Round your answer to two decimal places.
A random sample of 10,000 bottles of cola was taken to see whether the mean weight was 16 fluid ounces, as marked on the container. The null hypothesis is that the population mean is 16 ounces. Use the read-out below to test the hypothesis that the colas do not have a population mean of 16 fluid ounces. You do not have to do any calculations; just interpret the given data clearly and thoroughly in the context of the problem. | One-Sample T: ounces Test of u = 16 vs = 16 Variable Mean StDev SE Mean 95 CI T P ounces 10000 15.9988 0.0985 0.0010 (15.9969, 16.0007) -1.21 0.225
A sample of n = 7 scores has a mean ofM 5. After one new score is added to the sample, the new mean is found to be M 6. What is the value of the new score? (Hint: Compare the values for EX before and after the score was added.)
In a measurement of B two results were obtained, B1 = (8.3+/- 0.78) mT and B2 = (8.81+/- 0.20) mT . The error on the weighted/arithmetic mean is (Report your answer in mT with 3 significant figures)
Use z scores to compare the given values. The tallest living man at one time had a height of 252 cm. The shortest living man at that time had a height of 53.2 cm. Heights of men at that time had a mean of 172.68 cm and a standard deviation of 8.46 cm. Which of these two men had the height that was more extreme? see score past due Since the z score for the tallest man is z=] and the z score for the shortest man is z= the height that was more extreme. (Round to two decimal places.)
Q1]. [30%] The data for this question given in the table below come from the sample data folder of MINITAB. The data give you the monthly number of people employed (in units of 1000) in the retail trade industry in the state of Wisconsin from January 1970 to December 1974. Copy this timeseries data into an excel spreadsheet in your home area first before you start your analysis. You can use Excel to answer this question. Month 1970 1971 1972 1973 1974 1 322 322 330 348 361 2 317 318 326 345 354 3 319 320 329 349 357 4 323 326 337 355 367 5 327 332 345 362 376 6 328 334 350 367 381 7 325 335 351 366 381 8 326 336 354 370 383 9 330 335 355 371 384 10 334 338 357 375 387 11 337 342 362 380 392 12 341 348 368 385 396 (a) (b) (c) (d) Draw a time series plot of the data and comment on any noticeable patterns. Describe an appropriate time series model for this data, giving your reasons, and obtain estimates of the components of your model using the decomposition method. Using your model…
ANSWER MUST BE IN WHOLE NUMBER 1. Young researchers wants to estimate the average numbers of students spending their time on watching movies. The standard deviation from a previous study is 4 hours. How large a sample must be selected if they want to be: a. 95% confidence from the sample mean by 3.5 hours? b. 99% confidence from the sample mean by 2.5 hours? c. 99% confidence from the sample mean by 3.5 hours?

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