96 kg of ice has accumulated over 40 meters of a conductor whose 40 meters are 46 kg in a naked state. This conductor is III, where k=0.3. is in the ice zone. Since it is known that it is calculated with qb=k√d (kg/m) and the conductor is exposed to wind force at the same time with ice on it, calculate the q+bw value as kg/m. Frosted diameter D=√d2+216.46 qb mm (d bare conductor diameter, qb ice load in kg/m) Wind load qw=p x d x c x 10-3 N/m (no ice condition, different formula will be used in icy condition.) It will be taken as c=2 and p=294.3 N/m2
96 kg of ice has accumulated over 40 meters of a conductor whose 40 meters are 46 kg in a naked state. This conductor is III, where k=0.3. is in the ice zone. Since it is known that it is calculated with qb=k√d (kg/m) and the conductor is exposed to wind force at the same time with ice on it, calculate the q+bw value as kg/m. Frosted diameter D=√d2+216.46 qb mm (d bare conductor diameter, qb ice load in kg/m) Wind load qw=p x d x c x 10-3 N/m (no ice condition, different formula will be used in icy condition.) It will be taken as c=2 and p=294.3 N/m2
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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96 kg of ice has accumulated over 40 meters of a conductor whose 40 meters are 46 kg in a naked state. This conductor is III, where k=0.3. is in the ice zone.
Since it is known that it is calculated with qb=k√d (kg/m) and the conductor is exposed to wind force at the same time with ice on it, calculate the q+bw value as kg/m.
Frosted diameter D=√d2+216.46 qb mm (d bare conductor diameter, qb ice load in kg/m)
Wind load qw=p x d x c x 10-3 N/m (no ice condition, different formula will be used in icy condition.)
It will be taken as c=2 and p=294.3 N/m2
![qb= k√d kg/m
q+bw
D=√√d² +216,46 q, mm
qw=p.d.c.10-³ N/m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F007e0a06-6b04-4f2e-844d-4a3d7cb02e53%2F7adf1e79-6b81-4db2-b364-01b74543682d%2Fxvqdh9v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:qb= k√d kg/m
q+bw
D=√√d² +216,46 q, mm
qw=p.d.c.10-³ N/m
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