91 = +9 92 =-2.09 93 = +3.0q d- Given that q =+13 µC and d= 17 cm, a) What is the electric field (magnitude and direction) at the location of the point charge q? Show your work. 92= 13x 10X -2EL-26 A10bc E3 =3x106x13=39^106 %3D E =(8.99x16")(-26xo-)(-39) (17)2 =808.79 N -1.014A10 (8.992109) ( 31210,6) = 1213,183 N 289 V(1213.123)(-408.1yj? c1458.06C b) Find the net electrostatic force (magnitude and direction) exerted on the point charge q1 using the previous result. Show your work. F, 1213,183 +-809,79 =1404, 39 N 13 Useful formulas: ; E=k ;F= qE k=8.99 × 10° N.m²/C²; %3D

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