9.In a recent poll, 23% of the respondents supported candidate A, 19% supported candidate B.13% supported candidate C. and 45% were undecided. If 8 people are chosen at random, what is the probability that 3 people support candidate A, 2 support candidate B, 1 supports candidate C, and 2 are undecided? 00
9.In a recent poll, 23% of the respondents supported candidate A, 19% supported candidate B.13% supported candidate C. and 45% were undecided. If 8 people are chosen at random, what is the probability that 3 people support candidate A, 2 support candidate B, 1 supports candidate C, and 2 are undecided? 00
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
9.
![### Probability Exercises
**6. Coin Toss Probability:**
- An unbiased coin is tossed eight times. What is the probability of obtaining:
- (a) Less than 4 heads
- (b) More than 5 heads
Using your chart:
- (a) Probability: 0.3632 (Calculated as sum: 0.0078 + 0.0312 + 0.1094 + 0.2187)
- (b) Probability: 0.1445 (Calculated as sum: 0.1094 + 0.0312 + 0.0039)
**7. Lift Probability:**
- If the probability of getting a lift to work on any morning is 0.6, what is the probability that in a working week of five days, you will get a lift only twice?
Using your chart, the probability is 0.2304.
**8. Testing Pens for Faults:**
- From a consignment of pens, ten are tested. If none are faulty among those selected, the batch is returned. What is the probability that the consignment has at least 5% faulty pens?
Calculation: 0.0746 + 0.0101 + 0.0010 + 0.0001 = 0.0857
**9. Candidate Support:**
- In a survey, 23% support candidate A, 19% support candidate B, 13% support candidate C, and 45% are undecided. If 8 people are chosen, what's the probability that 3 support candidate A, 2 support candidate B, 1 supports candidate C, and 2 are undecided?
Calculation includes combinations:
\[
\frac{8!}{3! \times 1! \times 2! \times 2!} = \frac{40320}{24} = 1680
\]
**10. Blood Type Probability in Russia:**
- Population breakdown: 30% O+, 33% A+, 12% B+, 6% AB+, 7% O-, 8% A-, 3% B-, 1% AB-. For 15 selected individuals, what's the probability that 3 have O+, 2 A+, 3 B+, 2 AB+, 2 O-, 2 A-, 1 B-, and 1 AB-?
Round to 6 decimal](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F267ba495-9250-4421-b479-b7c447d19988%2F0ec317b5-eab6-44d4-baff-34317271b919%2Fucxc09d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Probability Exercises
**6. Coin Toss Probability:**
- An unbiased coin is tossed eight times. What is the probability of obtaining:
- (a) Less than 4 heads
- (b) More than 5 heads
Using your chart:
- (a) Probability: 0.3632 (Calculated as sum: 0.0078 + 0.0312 + 0.1094 + 0.2187)
- (b) Probability: 0.1445 (Calculated as sum: 0.1094 + 0.0312 + 0.0039)
**7. Lift Probability:**
- If the probability of getting a lift to work on any morning is 0.6, what is the probability that in a working week of five days, you will get a lift only twice?
Using your chart, the probability is 0.2304.
**8. Testing Pens for Faults:**
- From a consignment of pens, ten are tested. If none are faulty among those selected, the batch is returned. What is the probability that the consignment has at least 5% faulty pens?
Calculation: 0.0746 + 0.0101 + 0.0010 + 0.0001 = 0.0857
**9. Candidate Support:**
- In a survey, 23% support candidate A, 19% support candidate B, 13% support candidate C, and 45% are undecided. If 8 people are chosen, what's the probability that 3 support candidate A, 2 support candidate B, 1 supports candidate C, and 2 are undecided?
Calculation includes combinations:
\[
\frac{8!}{3! \times 1! \times 2! \times 2!} = \frac{40320}{24} = 1680
\]
**10. Blood Type Probability in Russia:**
- Population breakdown: 30% O+, 33% A+, 12% B+, 6% AB+, 7% O-, 8% A-, 3% B-, 1% AB-. For 15 selected individuals, what's the probability that 3 have O+, 2 A+, 3 B+, 2 AB+, 2 O-, 2 A-, 1 B-, and 1 AB-?
Round to 6 decimal
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