**Exercise 9.52**Let $ Y_1, Y_2, \ldots, Y_n $ be a random sample from a population with density function\[f(y \mid \theta) = \begin{cases} \frac{3y^2}{\theta^3}, & \text{for } 0 \leq y \leq \theta, \\0, & \text{elsewhere}.\end{cases}\]Show that $ Y_{(n)} = \max(Y_1, Y_2, \ldots, Y_n) $ is sufficient for $ \theta $.

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Answered: *9.52 Let Y₁, ₂,..., Y, be a random…

MATLAB: An Introduction with Applications

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*9.52 Let Y₁, ₂,..., Y, be a random sample from a population with density function 3y² f(y|0) = 8³ 0≤y≤0, elsewhere. Show that Y() = max(Y₁, Y₂,..., Y,) is sufficient for 0.