Let X1, .., Xn all be independent exponential distributions all with the same parameter 2. What is the distribution of the minimum of (X1, .., Xn)? In other words: a) what is the distribution of the smallest order statistic Y,? b) Specify both the pdf of the distribution and describe the distribution and its parameter

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**Analysis of Exponentially Distributed Random Variables**

Consider a set of independent exponential random variables \(X_1, \ldots, X_n\) each with the same rate parameter \(\lambda\).

**Objective:**
Determine the distribution of the minimum of these variables, specifically:

a) Identify the distribution of the smallest order statistic \(Y_1\).

b) Provide the probability density function (pdf) of this distribution and describe the distribution along with its parameters.

---

In exponential distributions, the minimum of several independent and identically distributed exponential random variables is also an exponential random variable. Thus:

- \(Y_1\), the minimum, follows an exponential distribution with a new rate parameter \(n\lambda\).
- The pdf of \(Y_1\) is given by:

\[ f_{Y_1}(y) = n\lambda e^{-n\lambda y}, \quad y \ge 0 \]

This scenario highlights a unique property of exponential distributions pertaining to minimum values, simplifying statistical modeling in numerous real-world applications.
Transcribed Image Text:**Analysis of Exponentially Distributed Random Variables** Consider a set of independent exponential random variables \(X_1, \ldots, X_n\) each with the same rate parameter \(\lambda\). **Objective:** Determine the distribution of the minimum of these variables, specifically: a) Identify the distribution of the smallest order statistic \(Y_1\). b) Provide the probability density function (pdf) of this distribution and describe the distribution along with its parameters. --- In exponential distributions, the minimum of several independent and identically distributed exponential random variables is also an exponential random variable. Thus: - \(Y_1\), the minimum, follows an exponential distribution with a new rate parameter \(n\lambda\). - The pdf of \(Y_1\) is given by: \[ f_{Y_1}(y) = n\lambda e^{-n\lambda y}, \quad y \ge 0 \] This scenario highlights a unique property of exponential distributions pertaining to minimum values, simplifying statistical modeling in numerous real-world applications.
Expert Solution
Step 1

a)

From the given information, the random variables X1,X2,....,Xn has an exponentially  distributed with parameter λ .

The distribution function for Xi is F(Xi)=1-e-λxi

The density function for Xi is f(Xi)=λe-λxi

The density function for the smallest order statistic Y1 is,

g(y1)=n1-FXin-1f(x)         =n1-1+e-λxn-1*λe-λx         =nλe-λxn-1+1        =nλe-nλx

Hence, the distribution of the smallest order statistic Y1 is Exponential distribution with parameter nλ.

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