9.36 Goodness of fit to a Poisson distribution. Refer to Example 5.30 (page 329) where a Poisson distribution is described as a model for the number of dropped calls on your cellphone per day. The mean number of calls is 2.1. In this setting, the probabilities for 0, 1, 2, and 3 or more dropped calls are 0.1225, 0.2572, 0.2700, and 0.3503, respectively. Suppose that you record the number of dropped calls per day for the next 100 days. Your observed counts of dropped calls are 11, 22, 28, and 39, respectively. Use a chi-square goodness of fit test to test the hypothesis that your calls are distributed according to this Poisson distribution.

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9.36 Goodness of fit to a Poisson distribution. Refer
to Example 5.30 (page 329) where a Poisson distribution
is described as a model for the number of dropped calls
on your cellphone per day. The mean number of calls
is 2.1. In this setting, the probabilities for 0, 1, 2, and 3
or more dropped calls are 0.1225, 0.2572, 0.2700, and
0.3503, respectively. Suppose that you record the number
of dropped calls per day for the next 100 days. Your
observed counts of dropped calls are 11, 22, 28, and 39,
respectively. Use a chi-square goodness of fit test to test
the hypothesis that your calls are distributed according to
this Poisson distribution.
Transcribed Image Text:9.36 Goodness of fit to a Poisson distribution. Refer to Example 5.30 (page 329) where a Poisson distribution is described as a model for the number of dropped calls on your cellphone per day. The mean number of calls is 2.1. In this setting, the probabilities for 0, 1, 2, and 3 or more dropped calls are 0.1225, 0.2572, 0.2700, and 0.3503, respectively. Suppose that you record the number of dropped calls per day for the next 100 days. Your observed counts of dropped calls are 11, 22, 28, and 39, respectively. Use a chi-square goodness of fit test to test the hypothesis that your calls are distributed according to this Poisson distribution.
EXAMPLE 5.30
Number of dropped calls. Suppose that the number of dropped calls on
your cell phone varies, with an average of 2.1 calls per day. If we assume
that the Poisson setting is reasonable for this situation, we can model
the daily count of dropped calls X using the Poisson distribution with
= 2.1. What is the probability of having no more than two dropped calls
tomorrow?
We can calculate P(X ≤ 2) either using software or the Poisson probabil-
ity formula. Using the probability formula:
P(X ≤2) = P(X= 0) + P(X = 1) + P(X = 2)
e-2.1 (2.1)⁰ e 2.1 (2.1)¹ e 2.1 (2.1)²
+
+
1!
2!
=
=
=
O!
0.1225 +0.2572 +0.2700
0.6497
Using the R software, the probability is
dpois (0,2.1) + dpois(1,2.1) + dpois(2,2.1)
[1] 0.6496314
Transcribed Image Text:EXAMPLE 5.30 Number of dropped calls. Suppose that the number of dropped calls on your cell phone varies, with an average of 2.1 calls per day. If we assume that the Poisson setting is reasonable for this situation, we can model the daily count of dropped calls X using the Poisson distribution with = 2.1. What is the probability of having no more than two dropped calls tomorrow? We can calculate P(X ≤ 2) either using software or the Poisson probabil- ity formula. Using the probability formula: P(X ≤2) = P(X= 0) + P(X = 1) + P(X = 2) e-2.1 (2.1)⁰ e 2.1 (2.1)¹ e 2.1 (2.1)² + + 1! 2! = = = O! 0.1225 +0.2572 +0.2700 0.6497 Using the R software, the probability is dpois (0,2.1) + dpois(1,2.1) + dpois(2,2.1) [1] 0.6496314
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