STATE: Andrew plans to retire in 40 years. He plans to invest part of his retirement funds in stocks, so he seeks out information on past returns. He learns that from 1966 to 2015, the annual returns on S&P 500 had mean 11.0% and standard deviation 17.0%. PLAN: The distribution of annual returns on common stocks is roughly symmetric, so the mean return over even a moderate number of years is close to Normal. We can use the Central Limit Theorem to make an inference. SOLVE: What is the probability, P1 , assuming that the past pattern of variation continues, that the mean annual return on common stocks over the next 40 years will exceed 10% ? (Enter your answer rounded to two decimal places.) Pi = What is the probability, p2, that the mean return will be less than 5% ? (Enter your answer rounded to two decimal places.) P2 =

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CONCLUDE: Select the correct conclusion based on the results.
There is about a 13% chance of getting average returns over 10% and a 3% chance of getting average returns less
than 5%.
There is about a 64% chance of getting average returns over 10% and a 1% chance of getting average returns less
than 5%.
O There is about a 33% chance of getting average returns over 10% and a 1% chance of getting average returns less
than 5%.
There is about a 75% chance of getting average returns over 10% and a 9% chance of getting average returns less
than 5%.
Transcribed Image Text:CONCLUDE: Select the correct conclusion based on the results. There is about a 13% chance of getting average returns over 10% and a 3% chance of getting average returns less than 5%. There is about a 64% chance of getting average returns over 10% and a 1% chance of getting average returns less than 5%. O There is about a 33% chance of getting average returns over 10% and a 1% chance of getting average returns less than 5%. There is about a 75% chance of getting average returns over 10% and a 9% chance of getting average returns less than 5%.
STATE: Andrew plans to retire in 40 years. He plans to invest part of his retirement funds in stocks, so he seeks out
information on past returns. He learns that from 1966 to 2015, the annual returns on S&P 500 had mean 11.0% and
standard deviation 17.0%.
PLAN: The distribution of annual returns on common stocks is roughly symmetric, so the mean return over even a
moderate number of years is close to Normal. We can use the Central Limit Theorem to make an inference.
SOLVE: What is the probability, p1, assuming that the past pattern of variation continues, that the mean annual return on
common stocks over the next 40 years will exceed 10% ? (Enter your answer rounded to two decimal places.)
Pi =
What is the probability, p2, that the mean return will be less than 5% ? (Enter your answer rounded to two decimal
places.)
P2 =
Transcribed Image Text:STATE: Andrew plans to retire in 40 years. He plans to invest part of his retirement funds in stocks, so he seeks out information on past returns. He learns that from 1966 to 2015, the annual returns on S&P 500 had mean 11.0% and standard deviation 17.0%. PLAN: The distribution of annual returns on common stocks is roughly symmetric, so the mean return over even a moderate number of years is close to Normal. We can use the Central Limit Theorem to make an inference. SOLVE: What is the probability, p1, assuming that the past pattern of variation continues, that the mean annual return on common stocks over the next 40 years will exceed 10% ? (Enter your answer rounded to two decimal places.) Pi = What is the probability, p2, that the mean return will be less than 5% ? (Enter your answer rounded to two decimal places.) P2 =
Expert Solution
Step 1

Let the returns be given by X.

Given,

X~N11,172

Let X be the mean returns over a period of 40 years.

So,

X~N11,17240 

to calculate p1=PX>10

PX>10=PX-1117240>10-1117240                 =PZ>-0.372                 =1-PZ<-0.372                 =1-ϕ-0.372Since the distribution is given to be symmetric, ϕ-z=ϕz                 =1-ϕ0.372                 =1-0.64431=0.35569value obtained from standard normal distribution tables.

Hence, 

p1=0.36 (rounded off to two decimal places)

 

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