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9.15 The source voltage in the phasor domain circuit in the accompanying figure is 25 /0" kV. Find the amplitude and phase angle of V, and I 1.5 kn j6 kn 125 Answer: V - 1868.15 /142.39* V; -1440 I: k= 125 /216.87 A. Ideal NOTE: Also iry Chapter Problem 9.77.

9.15 The source voltage in the phasor domain circuit in the accompanying figure is 25 /0" kV. Find the amplitude and phase angle of V, and I 1.5 kn j6 kn 125 Answer: V - 1868.15 /142.39* V; -1440 I: k= 125 /216.87 A. Ideal NOTE: Also iry Chapter Problem 9.77.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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9.15 The source voltage in thẹ phasor domain circuit in the accompanying figure is 25 /0° kV. Find the amplitude and phase angle of V, and 1.5 kf2 j6 kn 40 25: Answer: V - 1868.15 /142.39' V; /14,40 k = 125 /216.87* A. Ideal NOTE: Also try Chapter Problem 9.77.
Transcribed Image Text:9.15 The source voltage in thẹ phasor domain circuit in the accompanying figure is 25 /0° kV. Find the amplitude and phase angle of V, and 1.5 kf2 j6 kn 40 25: Answer: V - 1868.15 /142.39' V; /14,40 k = 125 /216.87* A. Ideal NOTE: Also try Chapter Problem 9.77.
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