9.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 6.00 x 103 M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2] was found to be 1.00 x 104 M (1.00 times 10 to the minus 4th power M) at equilibrium How many moles of Fe³+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

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Question 41
9.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 6.00 x 10³ M KSCN
(6.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1,00
x 10¹4 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at
equilibrium? Express your answer as a decimal number (no exponents).
Answer:
0.000029 (0.0000790) Mx (mol)
Transcribed Image Text:Question 41 9.00 mL of 9.00 x 10-3 M Fe(NO3)3 (9.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 5.00 mL of 6.00 x 10³ M KSCN (6.00 times 10 to the minus 3rd power M KSCN) along with 6.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1,00 x 10¹4 M (1.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents). Answer: 0.000029 (0.0000790) Mx (mol)
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