9. The thin ( 3 mm ) thick plastic panel shownin the figure is lowered from a ship to asitethefloor.Theconstructiononосeanplastic panel weighs ( 200 N ) in air and isCablelowered at a rate of ( 2 m/s ). Assuming thediyspanel remains vertically oriented, calculate= 1000ingthe tension force in the cable. Take ( p = 110 m/s ), andwater Plastickg/m', v1.31use;%3DPunel上.-3m.1/21/5Cplam = 1.328 / ReCpturb = 0.072 / Rej.

Weight = 200 N Thickness = 3 mm velocity = 2 m/s density = 1000 kg/m3 Find tension in the cable

9. The thin ( 3 mm ) thick plastic panel shown in the figure is lowered from a ship to a construction site on the ocean floor. The plastic panel weighs ( 200 N ) in air and is lowered at a rate of ( 2 m/s ). Assuming the panel remains vertically oriented, calculate the tension force in the cable. Take ( p = 1000 kg/m', v = 1.31 * 10“ m²/s ), and use; %3D *

9. The thin ( 3 mm ) thick plastic panel shown in the figure is lowered from a ship to a construction site on the ocean floor. The plastic panel weighs ( 200 N ) in air and is lowered at a rate of ( 2 m/s ). Assuming the panel remains vertically oriented, calculate the tension force in the cable. Take ( p = 1000 kg/m', v = 1.31 * 10“ m²/s ), and use; %3D *

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.

Question

9. The thin ( 3 mm ) thick plastic panel shown
in the figure is lowered from a ship to a
site
the
floor.
The
construction
on
осean
plastic panel weighs ( 200 N ) in air and is
Cable
lowered at a rate of ( 2 m/s ). Assuming the
diys
panel remains vertically oriented, calculate
= 1000
ing
the tension force in the cable. Take ( p = 1
10 m/s ), and
water Plastic
kg/m', v
1.31
use;
%3D
Punel
上.
-3m.
1/2
1/5
Cplam = 1.328 / Re
Cpturb = 0.072 / Rej.

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