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9. Miguel knows that in ACAT, point H and point Y are the midpoints of CĀ and CT respectively. Which of the following are true and can be used to solve for the length of AY given the length of ĀT? * 1 2' AT HA YT HY HA HY YT CH CH' ATr CY A. HA/CH = 1/2, YT/CY = 1/2, HYIAT = HA/CH, HY/AT = YT/CY 1 AT 1 AT 2 HY CA CT CT CH 2' CY 2' HY CY B. CA/CH = 1/2, CT/CY = 1/2, AT/HY %3D %3D = 1/2, AT/HY = CT/CY

9. Miguel knows that in ACAT, point H and point Y are the midpoints of CĀ and CT respectively. Which of the following are true and can be used to solve for the length of AY given the length of ĀT? * 1 2' AT HA YT HY HA HY YT CH CH' ATr CY A. HA/CH = 1/2, YT/CY = 1/2, HYIAT = HA/CH, HY/AT = YT/CY 1 AT 1 AT 2 HY CA CT CT CH 2' CY 2' HY CY B. CA/CH = 1/2, CT/CY = 1/2, AT/HY %3D %3D = 1/2, AT/HY = CT/CY

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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9. Miguel knows that in ACAT. point H and pointY are the midpoints of CĀ and CT respectively. Which of the following are true and can be used to solve for the length of AY given the length of ĀT? * 1 2' AT HA HY HA HY YT CH CH' ATr CY A. HA/CH = 1/2, YT/CY = 1/2, HYIAT = HA/CH, HY/AT = YT/CY 1 AT 1 AT 2 HY CA 1. CT CT CH 2' CY 2' HY CY B. CA/CH = 1/2, CT/CY = 1/2, AT/HY %3D %3D = 1/2, AT/HY = CT/CY
Transcribed Image Text:9. Miguel knows that in ACAT. point H and pointY are the midpoints of CĀ and CT respectively. Which of the following are true and can be used to solve for the length of AY given the length of ĀT? * 1 2' AT HA HY HA HY YT CH CH' ATr CY A. HA/CH = 1/2, YT/CY = 1/2, HYIAT = HA/CH, HY/AT = YT/CY 1 AT 1 AT 2 HY CA 1. CT CT CH 2' CY 2' HY CY B. CA/CH = 1/2, CT/CY = 1/2, AT/HY %3D %3D = 1/2, AT/HY = CT/CY
CY 1 HY %3D CH CH HY CY %3D HA' AT НА 2' YT 2' AT C. CH/HA = 1/2, CY/YT = 1/2, HY/AT = CH/HA, HY/AT = CY/YT %3D сH HY 1 HY %3D 2' AT CH 1 CY CY %3D %3D CA 2 CT CA' AT D. CH/CA = 1/2, CY/CT = 1/2, HY/AT %3D = CH/CA, HY/AT = CY/CT %3D !3!
Transcribed Image Text:CY 1 HY %3D CH CH HY CY %3D HA' AT НА 2' YT 2' AT C. CH/HA = 1/2, CY/YT = 1/2, HY/AT = CH/HA, HY/AT = CY/YT %3D сH HY 1 HY %3D 2' AT CH 1 CY CY %3D %3D CA 2 CT CA' AT D. CH/CA = 1/2, CY/CT = 1/2, HY/AT %3D = CH/CA, HY/AT = CY/CT %3D !3!
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