9. Locate all relative maxima, relative minima, and saddle points of the fol- lowing function f(x, y) = x² + y² - x²y. The second partial derivative test is: D(x, y) = fez(x, y) fyy (x, y) - (fxy(x, y))². •If D(xo, yo) > 0, and - if fax (xo, yo) > 0, then f has a relative (local) minimal at (xo, yo); then f has a relative (local) maximal at (xo, yo); if frx (xo, yo) <0, If D(xo, yo) <0, then (xo, yo) is a saddle point; • If D(xo, yo) = 0, no conclusion about (xo, yo).

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem 9: Locating Relative Maxima, Minima, and Saddle Points**

For the function:

\[ f(x, y) = \frac{1}{5}x^5 + \frac{1}{2}y^2 - x^2y \]

The second partial derivative test is given by:

\[ D(x, y) = f_{xx}(x, y) f_{yy}(x, y) - (f_{xy}(x, y))^2 \]

**Criteria for Evaluation:**

- If \( D(x_0, y_0) > 0 \), and:
  - If \( f_{xx}(x_0, y_0) > 0 \), then \( f \) has a relative (local) minimum at \( (x_0, y_0) \).
  - If \( f_{xx}(x_0, y_0) < 0 \), then \( f \) has a relative (local) maximum at \( (x_0, y_0) \).

- If \( D(x_0, y_0) < 0 \), then \( (x_0, y_0) \) is a saddle point.

- If \( D(x_0, y_0) = 0 \), no conclusion can be drawn about \( (x_0, y_0) \).
Transcribed Image Text:**Problem 9: Locating Relative Maxima, Minima, and Saddle Points** For the function: \[ f(x, y) = \frac{1}{5}x^5 + \frac{1}{2}y^2 - x^2y \] The second partial derivative test is given by: \[ D(x, y) = f_{xx}(x, y) f_{yy}(x, y) - (f_{xy}(x, y))^2 \] **Criteria for Evaluation:** - If \( D(x_0, y_0) > 0 \), and: - If \( f_{xx}(x_0, y_0) > 0 \), then \( f \) has a relative (local) minimum at \( (x_0, y_0) \). - If \( f_{xx}(x_0, y_0) < 0 \), then \( f \) has a relative (local) maximum at \( (x_0, y_0) \). - If \( D(x_0, y_0) < 0 \), then \( (x_0, y_0) \) is a saddle point. - If \( D(x_0, y_0) = 0 \), no conclusion can be drawn about \( (x_0, y_0) \).
Expert Solution
Step 1: Define the problem

The given function is f open parentheses x comma y close parentheses equals 1 fifth x to the power of 5 plus 1 half y squared minus x squared y

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