9. Given the spectrum F(@) of a signal ƒ(1) as shown below. If represen ts haif-cosine cycle truncated at a=±5, then f(1) is to be: 10 rect($1 -+recer(5t +)) F(o) 10 B. f)= sinc(10r -+sine(10r + c. SM) = ( sin e(St = 5) +sgn(5f + 5)]» jam -10 -5 10 10 D. f) ="(sinc(St - #)+sinc(5t +=))

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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9. Given the spectrum F(@) of a signal ƒ(1) as shown below. If represents half-cosine cycele
truncated at a = ±5, then f1) is to be:
(A) s)=
10
rect(51 –
+rect(5t +-
F(0)
B. f)= sinc(10r -+sinc(10r +
10
-( sin e(5t – 5) +sgn(5t +5)
jat
C. f(1) =
-10
-5
10
10
D. f)=(sin c(5r -)+sine(5/+#))
Transcribed Image Text:9. Given the spectrum F(@) of a signal ƒ(1) as shown below. If represents half-cosine cycele truncated at a = ±5, then f1) is to be: (A) s)= 10 rect(51 – +rect(5t +- F(0) B. f)= sinc(10r -+sinc(10r + 10 -( sin e(5t – 5) +sgn(5t +5) jat C. f(1) = -10 -5 10 10 D. f)=(sin c(5r -)+sine(5/+#))
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