Can you please explain each step of the solution especially the part I circled. Confused on how to get that answer. 9. Find a parametric equation for the line that is orthogonal to the surfacexyz = 2 at the point (1, 1, 2).Solution.The normal vector to the surface f(x, y, z) = 2 with f (x, y, z) = xyz isVf(7, y, 2) yzi + α2j + xyk.Thus, the normal vector at (x, y, z) = (1, 1,2) isi = Vf(1,1, 2) = 2i + 2j + k.The normal vector n(2, 2, 1) is a direction vector of the line, so aparametric equation of the line is(x, y, z) = (1, 1, 2) + t(2,2, 1),orx = 1+ 2t,y = 1+ 2t,z = 2+t.

Answered: Image /qna-images/answer/db5e1972-ef06-41d6-bae9-3407facb4c5b.jpg

Answered: 9. Find a parametric equation for the…

Math

Calculus

9. Find a parametric equation for the line that is orthogonal to the surface 2 at the point (1, 1, 2). Xyz

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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