9. Adriana is walking to the east at 3.00 m/s with a friend who is also walking east at 3.00 m/s, keeping a constant distance of 2.00 m from Adriana. The friend is talking, emitting a sound wave with power 34.0 mW. They are approached from behind by a bicyclist moving at 7.00 m/s east, ringing the bicycle's bell which emits with frequency 910 Hz and power 0.089 W. Air temperature is 17.0°C. At the instant when the bicyclist is 10.0 m behind Adriana, find: a) The frequency Adriana hears for the bicycle bell b) The intensity Adriana hears for the bicycle bell c) The intensity Adriana hears from her friend

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A, B and C 

### Problem Statement

Adriana is walking to the east at 3.00 m/s with a friend who is also walking east at 3.00 m/s, keeping a constant distance of 2.00 m from Adriana. The friend is talking, emitting a sound wave with power 34.0 mW. They are approached from behind by a bicyclist moving at 7.00 m/s east, ringing the bicycle’s bell which emits with frequency 910 Hz and power 0.089 W. The air temperature is 17.0°C. At the instant when the bicyclist is 10.0 m behind Adriana, find:

a) The frequency Adriana hears for the bicycle bell  
_________________________________________________  

b) The intensity Adriana hears for the bicycle bell  
_________________________________________________  

c) The intensity Adriana hears from her friend  
_________________________________________________  

d) The total sound level Adriana hears  
_________________________________________________

### Understanding Wave Phenomena

To solve this problem, we need to consider the Doppler effect, which describes the change in frequency of a wave in relation to an observer who is moving relative to the wave source. Intensity will also be altered by the distance from the source and can be calculated using the Inverse Square Law.

### Key Parameters:

1. **Velocity of sound in air**: The speed of sound can be approximated by the formula:
   \[
   v = 331.3 + 0.6 \times T \quad (\text{where T is the air temperature in Celsius})
   \]
   For T = 17.0°C,  
   \[
   v = 331.3 + 0.6 \times 17.0 = 331.3 + 10.2 = 341.5 \text{ m/s}
   \]

2. **Doppler Effect for Moving Observer and Source**:
   \[
   f' = f \times \left( \frac{v + v_{o}}{v - v_{s}} \right)
   \]
   where:
   - \(f'\) = observed frequency
   - \(f\) = emitted frequency (910 Hz for the bicycle bell)
   - \(v\) = speed of sound in air (341.5 m/s)
   - \(v_{o}\) = speed of observer (Adriana) = 3.00 m/s
   - \(
Transcribed Image Text:### Problem Statement Adriana is walking to the east at 3.00 m/s with a friend who is also walking east at 3.00 m/s, keeping a constant distance of 2.00 m from Adriana. The friend is talking, emitting a sound wave with power 34.0 mW. They are approached from behind by a bicyclist moving at 7.00 m/s east, ringing the bicycle’s bell which emits with frequency 910 Hz and power 0.089 W. The air temperature is 17.0°C. At the instant when the bicyclist is 10.0 m behind Adriana, find: a) The frequency Adriana hears for the bicycle bell _________________________________________________ b) The intensity Adriana hears for the bicycle bell _________________________________________________ c) The intensity Adriana hears from her friend _________________________________________________ d) The total sound level Adriana hears _________________________________________________ ### Understanding Wave Phenomena To solve this problem, we need to consider the Doppler effect, which describes the change in frequency of a wave in relation to an observer who is moving relative to the wave source. Intensity will also be altered by the distance from the source and can be calculated using the Inverse Square Law. ### Key Parameters: 1. **Velocity of sound in air**: The speed of sound can be approximated by the formula: \[ v = 331.3 + 0.6 \times T \quad (\text{where T is the air temperature in Celsius}) \] For T = 17.0°C, \[ v = 331.3 + 0.6 \times 17.0 = 331.3 + 10.2 = 341.5 \text{ m/s} \] 2. **Doppler Effect for Moving Observer and Source**: \[ f' = f \times \left( \frac{v + v_{o}}{v - v_{s}} \right) \] where: - \(f'\) = observed frequency - \(f\) = emitted frequency (910 Hz for the bicycle bell) - \(v\) = speed of sound in air (341.5 m/s) - \(v_{o}\) = speed of observer (Adriana) = 3.00 m/s - \(
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