9.) A motorcyclist who weighs 160 lbf accelerates his motorcycle at a rate of 10 ft/s² over a distance of 100 yards in 5 seconds. Convert all of the values given to SI units.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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**Problem 9: Conversion to SI Units**

A motorcyclist who weighs 160 lbf accelerates his motorcycle at a rate of 10 ft/s² over a distance of 100 yards in 5 seconds. Convert all of the values given to SI units.

**Explanation:**

To convert the given values to SI units, we will use the following conversions:

1. **Weight:** 1 pound-force (lbf) = 4.44822 newtons (N)
   \[
   160 \text{ lbf} \times 4.44822 \text{ N/lbf} = 711.7152 \text{ N}
   \]

2. **Acceleration:** 1 foot per second squared (ft/s²) = 0.3048 meters per second squared (m/s²)
   \[
   10 \text{ ft/s}^2 \times 0.3048 \text{ m/s}^2/\text{ft/s}^2 = 3.048 \text{ m/s}^2
   \]

3. **Distance:** 1 yard = 0.9144 meters
   \[
   100 \text{ yards} \times 0.9144 \text{ m/yard} = 91.44 \text{ m}
   \]

4. **Time:** The time is already given in seconds, which is an SI unit, so no conversion is necessary.

Using these conversions, the SI units for the given problem are:
- Weight: 711.7152 N
- Acceleration: 3.048 m/s²
- Distance: 91.44 m
- Time: 5 seconds

This problem demonstrates the conversion of various imperial units to the International System of Units (SI).
Transcribed Image Text:**Problem 9: Conversion to SI Units** A motorcyclist who weighs 160 lbf accelerates his motorcycle at a rate of 10 ft/s² over a distance of 100 yards in 5 seconds. Convert all of the values given to SI units. **Explanation:** To convert the given values to SI units, we will use the following conversions: 1. **Weight:** 1 pound-force (lbf) = 4.44822 newtons (N) \[ 160 \text{ lbf} \times 4.44822 \text{ N/lbf} = 711.7152 \text{ N} \] 2. **Acceleration:** 1 foot per second squared (ft/s²) = 0.3048 meters per second squared (m/s²) \[ 10 \text{ ft/s}^2 \times 0.3048 \text{ m/s}^2/\text{ft/s}^2 = 3.048 \text{ m/s}^2 \] 3. **Distance:** 1 yard = 0.9144 meters \[ 100 \text{ yards} \times 0.9144 \text{ m/yard} = 91.44 \text{ m} \] 4. **Time:** The time is already given in seconds, which is an SI unit, so no conversion is necessary. Using these conversions, the SI units for the given problem are: - Weight: 711.7152 N - Acceleration: 3.048 m/s² - Distance: 91.44 m - Time: 5 seconds This problem demonstrates the conversion of various imperial units to the International System of Units (SI).
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