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9. A block diagram of an indirect (Armstrong) FM transmitter is shown in Fig. below. Compute the maximum frequency deviation Af at of the output of the FM transmitter and the carrier frequency fe if f₁ = 200 kHz, fto = 10.8 MHz, Af₁ = 25 Hz, n₁ = 64 and n₂ = 48. f₂ = n₁f₁ mct) NBFM ↑ f₁ Af₁ Frequency Multiplier xn, Frequency ↑ Multiplier ↑ f3 XN₂ fc Af FLO s(t)

9. A block diagram of an indirect (Armstrong) FM transmitter is shown in Fig. below. Compute the maximum frequency deviation Af at of the output of the FM transmitter and the carrier frequency fe if f₁ = 200 kHz, fto = 10.8 MHz, Af₁ = 25 Hz, n₁ = 64 and n₂ = 48. f₂ = n₁f₁ mct) NBFM ↑ f₁ Af₁ Frequency Multiplier xn, Frequency ↑ Multiplier ↑ f3 XN₂ fc Af FLO s(t)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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9. A block diagram of an indirect (Armstrong) FM transmitter is shown in Fig. below. Compute the maximum frequency deviation Af at of the output of the FM transmitter and the carrier frequency fe if f₁ = 200 kHz, fto= 10.8 MHz, Af₁ = 25 Hz, n₁ = 64 and n₂ = 48. f₂ = n₁f₁ mct) NBFM f₁ Af₁ Frequency Multiplier xn, Frequency ↑ Multiplier 1 XN₂ fc Af f เอ s(t)
Transcribed Image Text:9. A block diagram of an indirect (Armstrong) FM transmitter is shown in Fig. below. Compute the maximum frequency deviation Af at of the output of the FM transmitter and the carrier frequency fe if f₁ = 200 kHz, fto= 10.8 MHz, Af₁ = 25 Hz, n₁ = 64 and n₂ = 48. f₂ = n₁f₁ mct) NBFM f₁ Af₁ Frequency Multiplier xn, Frequency ↑ Multiplier 1 XN₂ fc Af f เอ s(t)
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