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9. 1.4 g of glucose (C6H1206) is dissolved in 150 ml of water (final volume). What is the final number of moles and the molarity of the solution?

9. 1.4 g of glucose (C6H1206) is dissolved in 150 ml of water (final volume). What is the final number of moles and the molarity of the solution?

Biochemistry
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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**Problem 9:** 1.4 g of glucose (C₆H₁₂O₆) is dissolved in 150 ml of water (final volume). What is the final number of moles and the molarity of the solution? **Solution:** 1. **Calculate the number of moles of glucose:** The molar mass of glucose (C₆H₁₂O₆) = 6(C) + 12(H) + 6(O) = 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00 g/mol) = 180.16 g/mol Number of moles = mass (g) / molar mass (g/mol) = 1.4 g / 180.16 g/mol = 0.00777 moles 2. **Calculate the molarity of the solution:** Molarity (M) = moles of solute / volume of solution in liters Volume of solution = 150 ml = 0.150 L M = 0.00777 moles / 0.150 L = 0.0518 M Therefore, the final number of moles is 0.00777 moles and the molarity of the solution is 0.0518 M.
Transcribed Image Text:**Problem 9:** 1.4 g of glucose (C₆H₁₂O₆) is dissolved in 150 ml of water (final volume). What is the final number of moles and the molarity of the solution? **Solution:** 1. **Calculate the number of moles of glucose:** The molar mass of glucose (C₆H₁₂O₆) = 6(C) + 12(H) + 6(O) = 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00 g/mol) = 180.16 g/mol Number of moles = mass (g) / molar mass (g/mol) = 1.4 g / 180.16 g/mol = 0.00777 moles 2. **Calculate the molarity of the solution:** Molarity (M) = moles of solute / volume of solution in liters Volume of solution = 150 ml = 0.150 L M = 0.00777 moles / 0.150 L = 0.0518 M Therefore, the final number of moles is 0.00777 moles and the molarity of the solution is 0.0518 M.
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