9 Point charges of q = -3(nC), located in E = (V/m) uniform electric field are fixed to the two corners of the square with a = 1 (m) edge as in the figure. Find the magnitude of the electric field at point P in (V/m) units. (cos 45° = sin 45° = √2/2) A) 71√2 B) 26√2 C) 8√2 D) 25√2 E) 33√/2 a O 45

9 Point charges of q = -3(nC), located in E = (V/m) uniform electric field are fixed to the two corners of the square with a = 1 (m) edge as in the figure. Find the magnitude of the electric field at point P in (V/m) units. (cos 45° = sin 45° = √2/2) A) 71√2 B) 26√2 C) 8√2 D) 25√2 E) 33√/2 a O 45

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: The figure below shows a system consisting of three point charges, 9₁ = -0.691 µC, q2 = +0.235 µC,…

A: Three point charge at the vertices of a right triangle of base b=0.312 cm and height h=0.498 cm

Q: 6.00 µC 1.50 µC -2.00 µC |a) In the figure, three point charges lie on the x-axis as indicated. What…

Q: A positive point charge Q1Q1 = 2.1×10−5 CC is fixed at the origin of coordinates, and a negative…

Q: Three charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate…

Q: 3. In free space, a conductor sphere A with a radius a = 2 [m] lies in a conductor sphere B with a…

A: Step 1:

Q: In the figure a thin glass rod forms a semicircle of radius r = 3.03 cm. Charge is uniformly…

A: Given, thin glass rod forms a semicircle of radius r=3.03 cm= 3.03*10-2 m In the upper half charge…

Q: Two point charges, q₁ = 1.2 x 10-7 C and q₂ = -5.8 x 10-8 C, are held 35.0 cm apart. (Assume q2 is…

A: We are given 2 point charges and their separation distance. We are also given distance of point…

Q: 10.0cm as shown in the figure. The charges are qi=3.0µC E Three-point charges are placed…

A: Given:- three charges are given as q1= 3.0μCq2=-2.0 μC q3=3.0 μC r = 10 cm = 10× 10-2 m Find:-…

Q: In figure below, three point charges are fixed in place, and have charges q₁ = 92=+q and 93 +2q.…

Q: Two point charges are situated in a cartesian coordinate system as follow; q1 = 9.6 x 10-6 C @ the…

A: Given:-

Q: Calculate the magnitude of the electric field at a point which is 10 cm from a positive 23 μC…

A: N/C = (J/m)/C = J / (m x C) = (J/C)/m = V/m

Q: Three charges are placed on three corners of a square, as shown in the figure. Each side of the…

Q: A metal sphere of radius 12 cm carries a charge of +8.0 µC uniformly distributed over its surface.…

Q: A solid non conducting sphere of radius 1m carries a total charge of 10 C which is uniformly…

A: Given: The total charge on the sphere q = 10 C. The radius of the sphere r = 1 m.

Q: Two charges, Q1= 3.10 µC, and Q2= 5.60 µC are located at points (0,-3.00 cm ) and (0,+3.00 cm), as…

Q: Two point charges, q1 = 2.00 µC and q2 = -32.0 µC are positioned at (-d, -d) and (-4d, 4d)…

A: Two-point charges q1 = 2.00 μC = 2.00 × 10- 6 C q2 = - 32.0 μC = - 32.0 × 10- 6 C Location of q1…

Q: Electric charge is distributed is o(x, y) = 2xy, measured U 5 4 3 2- over the triang in coulumbs per

Q: The figure below shows two charges q1 and q2 located at a distance of 4 mm and 1 mm, respectively,…

Q: Three point charges q = +8 µC, q2 = +6 µC and q3 = -4 µC are fixed at the three corners of a square…

Q: Problem 13: Four point charges of equal magnitude Q = 65 nC are placed on the corners of a…

A: Let us draw a diagram of the situation showing all the forces which act on the lower left corner of…

Q: Four point charges are at the corners of a square of side a as shown in the figure below. Determine…

Q: Point charges of 26.0 µC and 45.0 µC are placed 0.450 m apart. (a) At what point (in m) along the…

Q: The figure shows three circular arcs centered at the origin of a coordinate system. On each arc, the…

Q: Electric charge is distributed over the semicircular region D shown below, with a charge density of…

A: Write the equation of the semicircle. x2+y2=22x2+y2=4y2=4−x2y=4−x2

Q: Three negative charges of -8.13 µC form an equilateral triangle with lengths 1.48 mm on each side. A…

A: Solution: Given Values, Three Negative charges are: q1=q2=q3=-8.13×10-6 CPositive…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

Point charges of q = -3(nC), located in E = (V/m) uniform electric field are fixed to the 9
two corners of the square with a = 1 (m) edge as in the figure. Find the magnitude of the
electric field at point P in (V/m) units. (cos 45° = sin 45° = √2/2)
A) 71√2
B) 26√2
C) 8√2
D) 25√/2
E) 33√2
A
E

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Here we define the diagram

VIEW

Step 2: Here we get magnitude of net electric field

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Three point charges q1 = +8 µC, q2 = +6 µC and q3 = -4 µC are fixed at the three corners of a square of sides 4.00 cm as shown in the FIGURE. Determine the magnitude and direction of the resultant electric field at the empty corner of the square. q1 92 93
The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 6.60 cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin. +2.0 μC (a) E = i (b) E = i –5.0 μ.C (a) -3.0 μC +4.0 μ C +1.0 μC +6.0 μ.C (b) -1.0 μC
Four charges are arranged at the corners of a square of side length, L = 35.0 cm. All four charges have the same magnitude q = 2.9 nC but the lower right charge is negative. Find the magnitude of the electric field at the center of the square. (Use k = 9.00 x 10°Nm²/C²) Provide the solution: ×10²N/C
Consider a square that is 1.0 m on a side. Charges are placed at the corners of the square as follows: +4.0 µC at (0, 0); +4.0 µC at (1, 1); +3.0 µC at (1, 0); -2.0 µC at (0, 1). What is the magnitude of the electric field (in N/C) at the square's center?
What is the magnitude of the electric field (in N/C) at the point P due to the two charges Q1 = 2.0 μC and Q2 = 7.0 μC with d = 3.0 m?
Using the symmetry of the arrangement, determine the direction of the electric field at the center of the square in Figure, given that qa = qb = −1.00 μC and qc = qd = +1.00 μC. Calculate the magnitude of the electric field at the location of q, given that the square is 5.00 cm on a side. Four point charges, one is q a, second is q b, third is q c, and fourth is q d, lie on the corners of a square. q is located at its center.
Two pairs of charges are shown in (Figure 1). Figure AB (b) | II II E F CD I 1 A B C I D ** I E 1 F + I G H I I J I I GHIJ I Part A At which point or points is the electric field zero in (Figure 1)(a)? Enter the letter or letters of the points in alphabetical order without commas. If there are no points where the electric field is zero, enter 0. E,F Submit Previous Answers Request Answer * Incorrect; Try Again; 12 attempts remaining Part B At which point or points is the electric field zero in (Figure 1)(b)? Enter the letter or letters of the points in alphabetical order without commas. If there are no points where the electric field is zero, enter 0. 8.5 Submit Previous Answers Request Answer X Incorrect; Try Again; 14 attempts remaining Review
1. Two positive point charges of magnitude IQl are separated by a distance d centered along the x-axis, as shown. y d/2 d/2 +IQI +IQI Find the electric field E (magnitude and direction, or coordinates) at the following positions (a) x = 0, y = 0 (b) х%3D0, у %3 +d
Four point charges have the same magnitude of 1.9 × 10-12 C and are fixed to the corners of a square that is 4.5 cm on a side. Three of the charges are positive and one is negative. Determine the magnitude of the net electric field that exists at the center of the square. Number i ! Units N/C
In a rectangular coordinate system a positive point charge q = 6.00 x 10-9 C is placed at the point x = +0.150m, y = 0, and an identical point charge is placed at x = -0.150m, y = 0. Find the x- and y-components, the magnitude, and the direction of the electric field at x = 0.300 m, y = 0. (with precise solution please) A. Ex = 129N/C and Ey = -510N/C with direction of 284 degrees counterclockwise from +x axis B. Ex = 2663.1 N/C and Ey = 0 to the +x direction C. Ex = 0 and Ey = 0 D. none of the above
At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 392 N/C. At a distance r2 from the charge, the field has a magnitude of 109 N/C. Find the ratio r2/r1.
4. The electric field near a charged, long, narrow, wire (think of monofilament, fishing line) was hinted at in homework 01 by solving a source charge integration problem. The electric field to the side of a charged, narrow wire (or rod) of length 2a was found to be 1 xdy Q 2a 1 B = 47², (^) (2² +2² ²2² = 425, (204) (2√2² + 2² Απερ (1). 3/2 ATTE a 1 Απε simpler expression E = Q o(x√x² + a² Then, one can take the limit as the length a tends toward infinity to obtain the much 20₁ 2TE T r. Here, we have transitioned from a distance r to the side of the wire (in the x-y plane) to a more general, radial distance out from the wire in any plane (not just the z-y plane). This same simpler equation can be very easily obtained by applying Gauss' Law using an appropriate Gaussian surface that surrounds part of an infinitely long, charged wire. Find this derivation (in a book or online) and rewrite it below. Add verbal explanations to take the reader through the derivation, equation by equation.