9-In an ideal dual combustion cycle conditions at the commencement of the adiabatic compression are 93kPa, 0.05m and 24 °C, respectively. The adiabatic compression volume ratio is 9:1. The constant volume heat addition pressure ratio is 1.5 and the constant pressure heat addition volume ratio is 2, if cp=1.05, cv=0.7745 kJ/kgK. Determine a- the pressure, volume and temperature at the state points of the cycle b- the thermal efficiency of the cycle c- the work done by the cycle P1=93 V1=0.05 T1=24 а- P2=1815 V2=0.0056 T2=371 P3=2722.5 V3=0.0056 T3=692 P4=2722.5 V4=0.0112 T4=1657 P5359 V5=0.05 T5=872 b(0.48), c(44.4kJ)

9-In an ideal dual combustion cycle conditions at the commencement of the adiabatic compression are 93kPa, 0.05m and 24 °C, respectively. The adiabatic compression volume ratio is 9:1. The constant volume heat addition pressure ratio is 1.5 and the constant pressure heat addition volume ratio is 2, if cp=1.05, cv=0.7745 kJ/kgK. Determine a- the pressure, volume and temperature at the state points of the cycle b- the thermal efficiency of the cycle c- the work done by the cycle P1=93 V1=0.05 T1=24 а- P2=1815 V2=0.0056 T2=371 P3=2722.5 V3=0.0056 T3=692 P4=2722.5 V4=0.0112 T4=1657 P5359 V5=0.05 T5=872 b(0.48), c(44.4kJ)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

i need the answer quickly

9-In an ideal dual combustion cycle conditions at the commencement of the adiabatic
compression are 93kPa, 0.05m³ and 24 °C, respectively. The adiabatic compression
volume ratio is 9:1. The constant volume heat addition pressure ratio is 1.5 and the
constant pressure heat addition volume ratio is 2, if cp=1.05, cv=0.7745 kJ/kgK.
Determine a- the pressure, volume and temperature at the state points of the cycle b-
the thermal efficiency of the cycle c- the work done by the cycle
P1=93
V1=0.05
T1=24
а-
P2=1815
V2=0.0056
T2=371
P3=2722.5
V3=0.0056
T3=692
P4=2722.5
V4=0.0112
T4=1657
P5359
V5=0.05
T5=872
b(0.48),
c(44.4kJ)

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