A metal rod is forced to move with constant velocity = 75.0 cm/s along two parallel metal rails, connected with a strip of metal at one end, as shown in the figure. A magnetic field B = 0.35 T points out of the page. The rails are seperated by 35.0 cm. a)What emf is generated? b)If the rod has a resistance of 17.0 Ω and the rails and connectors have negligible resistance, what is the current in the rod? c)At what rate is energy being tranferred to thermal energy?
A metal rod is forced to move with constant velocity = 75.0 cm/s along two parallel metal rails, connected with a strip of metal at one end, as shown in the figure. A magnetic field B = 0.35 T points out of the page. The rails are seperated by 35.0 cm. a)What emf is generated? b)If the rod has a resistance of 17.0 Ω and the rails and connectors have negligible resistance, what is the current in the rod? c)At what rate is energy being tranferred to thermal energy?
An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter18: The Universe
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Problem 5FIB
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A metal rod is forced to move with constant velocity = 75.0 cm/s along two parallel metal rails, connected with a strip of metal at one end, as shown in the figure. A magnetic field B = 0.35 T points out of the page. The rails are seperated by 35.0 cm.
a)What emf is generated?
b)If the rod has a resistance of 17.0 Ω and the rails and connectors have negligible resistance, what is the current in the rod?
c)At what rate is energy being tranferred to thermal energy?
![L
V
B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F127e312b-eb11-4e03-8035-8bed0448f3b8%2F8ccbcbf8-771a-4785-9e6b-3de854bc6d6b%2F22h7lf_processed.png&w=3840&q=75)
Transcribed Image Text:L
V
B
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Hello. Every single one of the answers given here is wrong.
![(8c30p31) A metal rod is forced to move with constant velocity = 75.0 cm/s along two parallel metal rails
of metal at one end, as shown in the figure. A magnetic field B = 0.35 T points out of the page. The rails
cm.
What emf is generated?
0.0672 V
Check the units for MKS and emf=v | B
Submit Answer Incorrect. Tries 1/4 Previous Tries
If the rod has a resistance of 17.0 2 and the rails and connectors have negligible resistance, what is the c
3.963e-3 A
Check the units for MKS and i=emf/R
Submit Answer Incorrect. Tries 1/4 Previous Tries
At what rate is energy being tranferred to thermal energy?
2.67e-4 W
Check the units for MKS and power i^2 R
Submit Answer Incorrect. Tries 1/4 Previous Tries
B
This discussion is closed.
Expert Solution
Step 1
Given,
v = 75 cm/s
B = 0.35 T
L = 35 cm
Step 2
a) Emf generated is given by
E = BLV = (0.35 T)*(0.35 m)*(0.55 m/s)
E = 0.0673 V
b) Given, R = 17.00
By Ohm's Law, induced current is
1 = E/R = 0.0673 V/ 17.00
1 = 3.963*10-³ A
By Lenz's Law, current is clockwise.
c) Rate of energy to thermal energy
P = 1²R = (3.963*10-³ A)² * (17)
P = 2.67*10-4 W
A metal rod is forced to move with constant velocity
⇓ C](https://content.bartleby.com/qna-images/question/127e312b-eb11-4e03-8035-8bed0448f3b8/973bf1ae-8f3a-4c62-8dd0-7da1074ce906/8y77qv_thumbnail.png)
Transcribed Image Text:(8c30p31) A metal rod is forced to move with constant velocity = 75.0 cm/s along two parallel metal rails
of metal at one end, as shown in the figure. A magnetic field B = 0.35 T points out of the page. The rails
cm.
What emf is generated?
0.0672 V
Check the units for MKS and emf=v | B
Submit Answer Incorrect. Tries 1/4 Previous Tries
If the rod has a resistance of 17.0 2 and the rails and connectors have negligible resistance, what is the c
3.963e-3 A
Check the units for MKS and i=emf/R
Submit Answer Incorrect. Tries 1/4 Previous Tries
At what rate is energy being tranferred to thermal energy?
2.67e-4 W
Check the units for MKS and power i^2 R
Submit Answer Incorrect. Tries 1/4 Previous Tries
B
This discussion is closed.
Expert Solution
Step 1
Given,
v = 75 cm/s
B = 0.35 T
L = 35 cm
Step 2
a) Emf generated is given by
E = BLV = (0.35 T)*(0.35 m)*(0.55 m/s)
E = 0.0673 V
b) Given, R = 17.00
By Ohm's Law, induced current is
1 = E/R = 0.0673 V/ 17.00
1 = 3.963*10-³ A
By Lenz's Law, current is clockwise.
c) Rate of energy to thermal energy
P = 1²R = (3.963*10-³ A)² * (17)
P = 2.67*10-4 W
A metal rod is forced to move with constant velocity
⇓ C
Solution
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